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Yakvenalex [24]
4 years ago
8

Imagine you are standing near a large rectangular pool and your friend asks you how far you think it is from one corner of the p

ool to the other, the long (diagonal) way. Explain how you could calculate that length (without getting wet) by only measuring the length and width of the pool. Then, make up a length and width (ex. 3 ft. by 4ft... etc.)... and perform the calculations to get the diagonal!
Mathematics
1 answer:
pickupchik [31]4 years ago
5 0

Answer:

See explanation below.

Step-by-step explanation:

A right triangle is a triangle that has a right angle (90º). In math, the Pythagorean theorem allows us to calculate the length of the sides of a right triangle.

In a right triangle, the legs are the two sides that meet at the 90º angle and the hypotenuse is the side that opposes the right angle. The Pythagorean Theorem tells us that the square of the hypotenuse equals the sum of the squares of the legs. In other words: c^2 =a^2 +b^2 where c is the hypotenuse and a and b are the legs.

Now, we can use this formula to calculate the diagonal of the pool if we just have the length and the width (these would be the legs of the triangle). We need to measure both the length and the width and then square both of them and sum up the squares: this would give us the square of the diagonal so we will only need to find its quadratic root and we will have the length of the diagonal.

For example, let's say we have a pool that is 3 ft by 4ft, using the formula we have:

Diagonal^2=3^2 +4^2 \\Diagonal^2 = 9+16\\Diagonal^2 = 25\\Diagonal = \sqrt{25} \\Diagonal =5

Therefore, in this case the diagonal would be 5 ft long.

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What's the GCF of 12a^2b^6, 28a^4 and 42ab^3? How did you find your answer?
8090 [49]

12a^2b^6=(2a)(6ab^6)\\\\28a^4=(2a)(14a^3)\\\\42ab^3=(2a)(21b^3)\\\\GCF(12a^2b^6,\ 28a^4,\ 42ab^3)=2a

6 0
3 years ago
The position vector for a particle moving on a helix is
topjm [15]

Answer:

a) 25.15

b)

   x = 1

   y = t

   z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)

c) (x,y) = (1, -2pi)

Step-by-step explanation:

a)

First lets calculate the velocity, that is, the derivative of c(t) with respect to t:

v(t) = (-sin(t), cos(t), 2t)

The velocity at t0=4pi is:

v(4pi) = (0, 1, 8pi)

And the speed will be:

s(4pi) = √(0^2+1^2+ (8pi)^2) = 25.15

b)

The tangent line to c(t) at t0 = 4pi has the parametric form:

(x,y,z) = c(4pi) + t*v(4pi)

Since

 c(4pi) = (1, 0, (4pi)^2)

The tangent curve has the following components:

x = 1

y = t

z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)

c)

The intersection with the xy plane will occurr when z = 0

This happens at:

  t1 = -2pi

Therefore, the intersection will occur at:

(x,y) = (1, -2pi)

6 0
3 years ago
Is this relation a function?
9966 [12]
Yes that is a function because every number has a pair that goes to each other once
5 0
3 years ago
I need help with 13 on both pictures. The first picture is the answer and the second picture is the question not getting the ans
natita [175]

Problem 13

If we want to multiply (x^3-3x^2+2x) with (x^3-2x^2+x), then we can set up a diagram shown below. The terms are along the outside. The stuff inside is the result of multiplying each pair of outer terms.

  • Example: x^3 times x^3 = x^6 in the top left corner
  • Another example: 2x times x = 2x^2 in the bottom right corner.

This is known as the box method to keep track of all the terms multiplied.

Once the table is filled out, we add up each term inside the boxes. Combine like terms if possible. Notice that I color-coded the like terms (eg: the x^3 terms are in green boxes).

The final answer is x^6 - 5x^5 + 9x^4 - 7x^3 + 2x^2

6 0
2 years ago
6 + (1 + 9) = 16, so<br> (6 + _) + 9 = '16
horsena [70]

Answer:

1

Step-by-step explanation:

Adding the same positive numbers will always give you the same answers, right here all your doing is switching the 9 and the 1 ... so 1

3 0
3 years ago
Read 2 more answers
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