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3 years ago

The following numbers divisible by 4 and 8 a) 726352

Mathematics

1 answer:

Mariulka [41]3 years ago

5 0

Step-by-step explanation:

: last two digits are 52 and 52 is divisible by 4. Therefore, 726352 is also divisible by 4. by 8: last three digits are 352 and 352 is divisible by 8. Therefore, 726352 is also divisible by 8.

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The table below shows the different combinations of honey and oats that can be used in making granola.

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Step-by-step explanation:

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3 years ago

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-5a to the second power-7a

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4 years ago

The following represents the probability distribution for the daily demand of microcomputers at a local store. Demand Probabilit

konstantin123 [22]

Answer:

The correct answer is 2.2.

Step-by-step explanation:

The following represents the probability distribution for the daily demand of microcomputers at a local store:

Demand Probability

f(0)= .1

f(1)= .2

f(2)= .3

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Thus the expected value of demand is given by

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4 years ago

Making art and can help you find a difference 13 - 5

Genrish500 [490]

Answer:

Here's how to solve

Step-by-step explanation:

Okay so 13 -5

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3 years ago

To find the product of (−2√20k)(5√8k3), first write using a single radical. Which expression is equivalent to the given product?

ad-work [718]

Answer:

Assuming the variable is included under the radical,

-40k²√(10)

Step-by-step explanation:

$(-2\sqrt{20k})(5\sqrt{8k^3})$

First we will simplify the first factor,

$-2\sqrt{20k}$

We will write 20 as a product of factors:

$-2\sqrt{4*5k}$

We know the square root of 2 is 2, so we pull a 2 out:

$-2(2)\sqrt{5k}\\\\=-4\sqrt{5k}$

Now we will simplify the second factor,

$5\sqrt{8k^3}$

We will rewrite 8 as a product of factors, as well as the variable:

$5\sqrt{2*4*k^2*k}$

The square root of 2 is 2, so we pull a 2 out. Additionally, the square root of k² is k, so we pull that out:

$5(2)(k)\sqrt{2k}\\\\=10k\sqrt{2k}$

This gives us the product

$(-4\sqrt{5k})(10k\sqrt{2k})$

Multiplying the coefficients, we have

$-4(10k)(\sqrt{5k})(\sqrt{2k})\\\\=-40k(\sqrt{5k})(\sqrt{2k})$

Multiplying the two radicals, we have

$-40k\sqrt{5k*2k}\\\\-40k\sqrt{10k^2}$

The square root of k² is k, so we pull a k out, leaving

$-40k(k)\sqrt{10}\\\\=-40k^2\sqrt{10}$

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4 years ago

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The following numbers divisible by 4 and 8 a) 726352​

The following numbers divisible by 4 and 8 a) 726352