The mass of NiCl₂•6HO₂ needed to prepare a 0.035 M 500 mL solution of NiCl₂•6HO₂ is 4.165 g
<h3>What is molarity? </h3>
This is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:
Molarity = mole / Volume
<h3>How to determine the mole of NiCl₂•6HO₂</h3>
- Molarity = 0.035 M
- Volume = 500 mL = 500 / 1000 = 0.5 L
Mole = Molarity × Volume
Mole of NiCl₂•6HO₂ = 0.035 × 0.5
Mole of NiCl₂•6HO₂ = 0.0175 mole
<h3>How to determine the mass of NiCl₂•6HO₂</h3>
- Mole of NiCl₂•6HO₂ = 0.0175 mole
- Molar mass of NiCl₂•6HO₂ = 238 g/mol
Mass = mole × molar mass
Mass of NiCl₂•6HO₂ = 0.0175 × 238
Mass of NiCl₂•6HO₂ = 4.165 g
Thus, 4.165 g of NiCl₂•6HO₂ is needed to prepare the solution
Learn more about molarity:
brainly.com/question/15370276
Answer:
Matter is a physical substance that contains mass. A substance is a particular kind of matter with uniform chracteristics.
Explanation:
Remeber that matter is anything that has mass and takes up space :)
Answer : The correct option is, (C) Both the atomic mass and the atomic number increase from left to right.
Explanation :
The general trend of atomic number and atomic mass in the periodic table is,
Both atomic number and atomic mass increase from left to right and decreases from right to left in the periodic table due to the addition of the number of neutrons and the number of protons in the nucleus.
Hence, the correct option is, (C) Both the atomic mass and the atomic number increase from left to right.
A measure of peak separation in a chromatographic method that equals the difference in retention time for two components divided by the average of their peak widths is the definition of resolution.
Retention time can be referred to as the amount of time a solute spends in the stationary and mobile phases of a column.
The analyte's interaction with the stationary phase determines the longer retention period.
The duration of retention will increase as the interaction becomes more strong.
Resolution is defined as the peak separation in a chromatographic procedure that is equal to the difference in retention time for two components divided by the average of their peak widths.
Learn more about resolution
brainly.com/question/14300434
#SPJ4