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Ierofanga [76]
3 years ago
13

Why cant chemical changes be reversed

Chemistry
1 answer:
kotykmax [81]3 years ago
4 0

Answer:

Throughout the explanation section, the reason behind the given statement is described.

Explanation:

  • The chemicals thus produced were indeed opposite or separate from the reaction mixture, this same reaction wouldn’t change when it's more balanced than some of the reactants.
  • Another reason is that the development of advanced organisms, as well as chemical alterations, is irreversible throughout nature cant undo the chemical modifications.

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Calculate the mass of water produced when 7.26 g of butane reacts with excess oxygen
MaRussiya [10]

Answer:

11.3 g.

Explanation:

Hello there!

In this case, since the combustion of butane is:

C_4H_{10}+\frac{13}{2} O_2\rightarrow 4CO_2+5H_2O

Thus, since there is a 1:5 mole ratio between butane and water, we obtain the following mass of water:

m_{H_2O}=7.26gC_4H_{10}*\frac{1molC_4H_{10}}{58.14gC_4H_{10}}*\frac{5molH_2O}{1molC_4H_{10}}  *\frac{18.02gH_2O}{1molH_2O}

Therefore, the resulting mass of water is:

m_{H_2O}=11.3gH_2O

Best regards!

4 0
3 years ago
SO2(g) + NO2(g) ↔ SO3(g) + NO(g) Kc = 0.33 A reaction mixture contains 0.41 M SO2, 0.14 M NO2, 0.12 M SO3 and 0.14 M NO. Which o
stepladder [879]

Answer:

The reaction will shift in the direction of products.

Explanation:

<u>Step 1:</u> Data given

A reaction mixture contains:

0.41 M SO2

0.14 M NO2

0.12 M SO3

0.14 M NO

<u>Step 2:</u> The balanced equation

O2(g) + NO2(g) ↔ SO3(g) + NO(g)      Kc = 0.33

<u>Step 3:</u> Define the direction of the shift of  reaction:

When Q<K, there are more reactants than products. As a result, some of the reactants will become products, causing the reaction to shift to the right.

When Q>K, there are more products than reactants. To decrease the amount of products, the reaction will shift to the left and produce more reactants.

When Q=K, the system is at equilibrium and there is no shift to either the left or the right.

<u>Step 4:</u> Calculate Q

Q = [NO][SO3]/[SO2][NO2]

Q = (0.14 *0.12)/(0.41*0.14)

Q = 0.0168/0.0574

Q = 0.293

Q<Kc

This means there are more reactants than products. Thud, some of the reactants will become products, causing the reaction to shift to the right.

The reaction will shift in the direction of products.

8 0
3 years ago
A 0.1 M NaCl solution and a 0.2 M glucose solution are separated by a membrane that is impermeable to these solutes but is perme
katovenus [111]

nothing will happen

if you calculate the water potiential for both solutions

you get 2(0.1)(R)(T) and 1(0.2)(R)(T)

which is the same thing, so its isotonic.

7 0
2 years ago
A diver exhales a bubble with volume of 250 mL at pressure of 2.4 atm and temperature of 15 C. How many gas particulate in this
erastova [34]

Answer:

1.5x10²² particulates

Explanation:

Assuming ideal behaviour, we can solve this problem by using the <em>PV=nRT </em>formula, where:

  • P = 2.4 atm
  • V = 250 mL ⇒ 250 / 1000 = 0.250 L
  • n = ?
  • R = 0.082 atm·L·mol⁻¹·K⁻¹
  • T = 15 °C ⇒ 15 + 273 = 288 K

We <u>input the given data</u>:

  • 2.4 atm * 0.250 L = n * 0.082 atm·L·mol⁻¹·K⁻¹ * 288 K

And <u>solve for n</u>:

  • n = 0.025 mol

Finally we <u>calculate how many particulates are there in 0.025 moles</u>, using <em>Avogadro's number</em>:

  • 0.025 mol * 6.023x10²³ particulates/mol = 1.5x10²² particulates
6 0
2 years ago
Calculate the AHrxn from the AH of formation for the following reaction. C2H4(g) + 302(g) 2C02(g) + 2H20(1). Formation AH values
RSB [31]

Answer

A. -1305 kJ

Explanation

Given:

Equation: C2H4(g) + 302(g) ---- > 2C02(g) + 2H20(l).

Formation ΔH values:

​​for C2H4(g) = 52.30 kJ/mol,

for 02(g) = 0 kJ/mol,

for CO2(g) = -393.5 kJ/mol, and

for H20(1) = -285.8kJ/mol.

What to find:

The ΔHrxn from the ΔH of formation for the given reaction.

Step-by-step solution:

ΔHrxn = (Sum of ΔH formation for the product) - (Sum of ΔH formation for the reactants).

ΔHrxn = (ΔH for 2CO2(g) + ΔH for 2H2O(l)) + (ΔH for C2H4(g) + ΔH for 3O2(g))

ΔHrxn = [(2 x -393.5) + (2 x -285.8)] + [52.30 + (3 x 0)]

ΔHrxn =(-787.0 - 571.6) + (52.30 + 0)

ΔHrxn = -1358.6 + 52.30

ΔHrxn = -1306.3 kJ

so the closest answer is A. -1305 kJ

4 0
1 year ago
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