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Ierofanga [76]
3 years ago
13

Why cant chemical changes be reversed

Chemistry
1 answer:
kotykmax [81]3 years ago
4 0

Answer:

Throughout the explanation section, the reason behind the given statement is described.

Explanation:

  • The chemicals thus produced were indeed opposite or separate from the reaction mixture, this same reaction wouldn’t change when it's more balanced than some of the reactants.
  • Another reason is that the development of advanced organisms, as well as chemical alterations, is irreversible throughout nature cant undo the chemical modifications.

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labwork [276]

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Explanation: hope u get it right

4 0
2 years ago
Calculate the energy required to heat 322.0g of ethanol from −2.2°C to 19.6°C . Assume the specific heat capacity of ethanol und
just olya [345]

Answer:

There is 17.1 kJ energy required

Explanation:

Step 1: Data given

Mass of ethanol = 322.0 grams

Initial temperature = -2.2 °C = 273.15 -2.2 = 270.95K

Final temperature = 19.6 °C = 273.15 + 19.6 = 292.75 K

Specific heat capacity = 2.44 J/g*K

Step 2: Calculate energy

Q = m*c*ΔT

⇒ m = the mass of ethanol= 322 grams

⇒ c = the specific heat capacity of ethanol = 2.44 J/g*K

⇒ ΔT = T2 - T1 = 292.75 - 270.95 = 21.8 K

Q = 322 * 2.44 * 21.8 = 17127.8 J = 17.1 kJ

There is 17.1 kJ energy required

3 0
3 years ago
What happens after you leave oil and vinegar in a glass for a few minutes?
MAVERICK [17]

Answer:

An emulsion is formed.

Explanation:

An association (emulsion) of two liquids is formed, in this case oil and vinegar, which when stirred, said mixture will separate.

3 0
3 years ago
NItrogen in air reacts at high temperature to form NO2 according to the reaction:
Rina8888 [55]

Answer:

The correct answer is option E.

Explanation:

Structures for the reactants and products are given in an aimage ;

Number of double bonds in oxygen gas molecule = 1

Number of double bonds in nitro dioxide gas molecule = 1

Number of single bond in in nitro dioxide gas molecule = 1

Number of triple bonds in nitrogen gas molecule = 1

N_2+2O_2\rightarrow 2NO_2,\Delta H=?

\Delta H=[2 mol\times \Delta H_{f,NO_2}]-[1 mol\times \Delta H_{f,N_2}-2 mol\times \Delta H_{f,O_2}]

\Delta H_{f,NO_2}=33.18 kJ/mol

\Delta H_{f,N_2}=0 (pure element)

\Delta H_{f,O_2}=0 (pure element )

\Delta H=2 mol\times 33.18 kJ/mol=66.36kJ=15.86 kcal

The enthalpy of the given reaction is 15.86 kcal.

6 0
3 years ago
What is meant by the negative sign in an answer like"-46.8kJ"? When would you use a positive sign
MA_775_DIABLO [31]
It’s positive when you use energy for work
3 0
3 years ago
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