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vodka [1.7K]
3 years ago
11

A student melts 50.0 grams of ice using 16650 J of energy. What is the heat of fusion of ice?

Chemistry
2 answers:
san4es73 [151]3 years ago
8 0

Answer:

L = 330.0 J/g

Explanation:

The heat of fusion is the energy necessary to transform 1 gram of the solid compound in its liquid phase. Fusion requires that the systems gain heat, so it's an endothermic process.

The energy (Q) is relacionated to the mass of the compound (m) and its heat of fusion (L):

Q = mL

16650 = 50.0L

L = 16650/50

L = 333.0 J/g

Shkiper50 [21]3 years ago
6 0
Heat fusion is the amount of energy required to convert one mole of ice into water, 16650J is per 50g so if we divide 16650 by 50 we find it per gram: 16650/50 = 333J/g or 0.33KJ/g

hope that helps :)
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son4ous [18]

Answer: The molar enthalpy change is 73.04 kJ/mol

Explanation:

HCl+NaOH\rightarrow NaCl+H_2O

moles of HCl= molarity\times {\text {vol in L}}=0.415mol/L\times 0.1=0.0415mol

As NaOH is in excess 0.0415 moles of HCl reacts with 0.0415 moles of NaOH.

volume of water = 100.0 ml + 50.0 ml = 150.0 ml

density of water = 1.0 g/ml

mass of water = volume \times density=150.0ml\times 1.0g/ml=150.0g

q=m\times c\times \Delta T

q = heat released

m = mass  = 150.0 g

c = specific heat = 4.184J/g^0C

\Delta T = change in temperature = 4.83^0C

q=150.0\times 4.184\times 4.83

q=3031.3J

Thus 0.0415 mol of HCl produces heat = 3031.3 J

1 mol of HCL produces heat = \frac{3031.3}{0.0415}\times 1=73043.3J=73.04kJ

Thus molar enthalpy change is 73.04 kJ/mol

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