Step-by-step explanation:
Let ABCD be a rhombus. So, AC (AC = 14 cm) and BD (BD=48 cm) will be its diagonals. Let us assume that diagonals are intersecting at point O.
Since, diagonals of a rhombus are perpendicular bisector.
Hence, length of a side (or all) is 25 cm.
N=155. And since the other outer angle is also 155. And since the sum of all other angles is 360, you would take 360-155-155. That is 310. And so you would take 360-310=50. Since there is two angles, both m and p are equal to 25
14/50 = 7/25
CosX = adjacent side of X/hypotenuse of X = 14/50 = 7/25
Answer:
3 units
Step-by-step explanation:
∠A = ∠E (same arc BD)
∠X share
ΔXDA similar to ΔXBE
XE / XA = XB / XD
(3 + DE) / 9 = 2 / 3
9 + 3DE = 18
3DE = 9
DE = 3
90% of <span>£41 = 90/100 × 41 = </span><span>£36.9
</span>£41 decreased by 90% = 41 - 36.9 = <span>£4.1</span>
