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2 years ago

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Voting Yolanda’s club has 35 members, it’s rule require that 60% of them must be presented for any vote. At least how many membe

rs must be presented to have a vote?

1 answer:

ElenaW [278]2 years ago

4 0

You would need to multiply 35 x .6 (which is 60%).
35 x .6 = 21, so at least 21 members need to be present to vote.

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Please help me i dont know what i am doing

Olenka [21]

Answer:

answer is 1.25
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2 years ago

A vegetable garden with an area of 200 square feet is to be fertilized. If the length of the garden is 1 foot less than three ti

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Ok so I like to go in steps with these questions- first draw a picture and identify your variables.

W=width
L= 3w-1

Now we know that length times width gets us area so we plug in our variables into the area equation.

200 = w(3w-1)

When you foil that equation you end up with a quadratic : 3w^2-w-200 = 0

Either factor that or use the quadratic formula to get
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Since you can't have a negative dimension you need to use 8.33 and plug it back into your length equation.

Final answer:

w= 8.33ft
l= 23.99ft

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3 years ago

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What is the value of x in the figure ?

morpeh [17]

Step-by-step explanation:

$2x+15= 145°$

( vertically opposite angles)

$2x=145-15 = 130$

$x = \frac{130}{2}$

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3 years ago

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The point which divides the line segment joining the points (2, -6) and (3, 4) in the ratio 1 : 2 internally lies in the

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3 years ago

Given the parabola below, find the endpoints of the latus rectum. (x-2)^2=-20(y+2)

Shtirlitz [24]

Answer:

The endpoints of the latus rectum are $(12, -7)$ and $(-8, -7)$ .

Step-by-step explanation:

A parabola with vertex at point $C(x, y) = (h,k)$ and whose axis of symmetry is parallel to the y-axis is defined by the following formula:

$(x-h)^{2} = 4\cdot p \cdot (y-k)$ (1)

Where:

$y$ - Independent variable.

$x$ - Dependent variable.

$p$ - Distance from vertex to the focus.

$h$ , $k$ - Coordinates of the vertex.

The coordinates of the focus are represented by:

$F(x,y) = (h, k+p)$ (2)

The <em>latus rectum</em> is a line segment parallel to the x-axis which contains the focus. If we know that $h = 2$ , $k = -2$ and $p = -5$ , then the latus rectum is between the following endpoints:

By (2):

$F(x,y) = (2, -2-5)$

$F(x,y) = (2,-7)$

By (1):

$(x-2)^{2} = -20\cdot (-7+2)$

$(x-2)^{2} = 100$

$x - 2 = \pm 10$

There are two solutions:

$x_{1} = 2 + 10$

$x_{1} = 12$

$x_{2} = 2-10$

$x_{2} = -8$

Hence, the endpoints of the latus rectum are $(12, -7)$ and $(-8, -7)$ .

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2 years ago