A dilation is a transformation
, with center O and a scale factor of k that is not zero, that maps O to itself and any other point P to P'.
The center O is a fixed point, P' is the image of P, points O, P and P' are on the same line.
In a dilation of
the scale factor, k is mapping the original figure to the image in such a way that the
distances from O to the vertices of the image are k times the distances
from O to the original figure. Also the size of the image are k times the
size of the original figure.
Thus for a dilation using the rule
results in the distance of the image form O being twice the distance of the original point from O.
Therefore, it can be observed that the scale factor of the dilation, k, is 2.
Answer:
portion b is 17 ounces. portion c is 34 ounces.
Step-by-step explanation:
portion a is 8.25 ounces and since portion bis twice that amount u multiply 8.25 by 2 and u get 17, that is portion b. portion c is twice portion b which means u have to multiply 17 by 2 which is 34, which makes portin c 34 ounces.
Answer:
A. Opens up with a vertex at (5,-4)
Step-by-step explanation:
Apex
Answer:
x = -2
x = 8
Step-by-step explanation:
Excluded values are the ones which make the denominator zero
3x² + x - 10
3x² + 6x - 5x - 10
3x(x + 2) - 5(x + 2)
(x + 2)(3x - 5)
x² - 6x - 16
x² - 8x + 2x - 16
x(x - 8) + 2(x - 8)
(x - 8)(x + 2)
[(x + 2)(3x - 5)] ÷ [(x - 8)(x + 2)]
(3x - 5)/(x - 8)
So excluded values are 8, -2
Answer:
C) The Spearman correlation results should be reported because at least one of the variables does not meet the distribution assumption required to use Pearson correlation.
Explanation:
The following multiple choice responses are provided to complete the question:
A) The Pearson correlation results should be reported because it shows a stronger correlation with a smaller p-value (more significant).
B) The Pearson correlation results should be reported because the two variables are normally distributed.
C) The Spearman correlation results should be reported because at least one of the variables does not meet the distribution assumption required to use Pearson correlation.
D) The Spearman correlation results should be reported because the p-value is closer to 0.0556.
Further Explanation:
A count variable is discrete because it consists of non-negative integers. The number of polyps variable is therefore a count variable and will most likely not be normally distributed. Normality of variables is one of the assumptions required to use Pearson correlation, however, Spearman's correlation does not rest upon an assumption of normality. Therefore, the Spearman correlation would be more appropriate to report because at least one of the variables does not meet the distribution assumption required to use Pearson correlation.
