Answer:
1) (3 - 6x)(-8) = (-8)(3) - (-8)(6x) = -24 - (-48x) = -24 + 48x = 48x - 24
2) (-12)(2x - 3) = (-12)(2x) - (-12)(3) = -24x - (-36) = -24x + 36 = 36 - 24x
3) (10 - 2x)9 = (9)(10) - (9)(2x) = 90 - 18x
4) (-5)(11x - 2) = (-5)(11x) - (-5)(2) = -55x - (-10) = -55x + 10 = 10 - 55x
5) (1 - 9x)(-10) = (-10)(1) - (-10)(9x) = -10 - (-90x) = -10 + 90x = 90x - 10
6) (-6)(x + 8) = (-6)(x) + (-6)(8) = -6x + (-48) = -6x - 48
7) (-4 + 3x)(-8) = (-8)(-4) + (-8)(3x) = 32 + (-24x) = 32 - 24x
8) (-5)(1 - 11x) = (-5)(1) - (-5)(11x) = -5 - (-55x) = -5 + 55x = 55x -5
9) (-12x + 14)(-5) = (-5)(-12x) + (-5)(14) = 60x + (-70) = 60x - 70
Step-by-step explanation:
The distributive property is a(b + c) = ab + ac
Use division or long division (ignore the decimal point)
Then put the decimal in the same spot as the dividend (the number being divided)
Diagram missing.
Question interpreted as:
ABC is a right triangle right angled at A.
BC=17 feet
angle C = 35 degrees.
AC=BCcos(35)=17*0.8192=13.93 feet to the nearest 1/100th of a foot.
Answer:
- time: t = -0.3
- minimum: v = 0.55
Step-by-step explanation:
For quadratic ax^2 + bx + c, the extreme value is found at x=-b/(2a). For your quadratic, the minimum is found at ...
t = -(3)/(2(5))
t = -0.3 . . . . . time of minimum velocity
__
The value of velocity at that time is ...
v = 5(-0.3)^2 +3(-0.3) +1 = 5(.09) -.9 +1
v = 0.55 . . . . . value of minimum velocity
