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3 years ago

Can someone help me on this

Mathematics

2 answers:

nydimaria [60]3 years ago

8 0

Answer:

10√3 feet

Step-by-step explanation:

In a 30-60-90 triangle;

-Long leg = long leg

-Short leg = 1/2 * long leg

-2nd longest leg = short leg * √3

-Long leg = 20

-Short leg = 1/2 * long leg = 10

-2nd longest leg = short leg * √3 = 10√3

WINSTONCH [101]3 years ago

3 0

Answer: 17.3ft

Step-by-step explanation:

Using sine rule

((sin base)/20)= ((sin suzy)/y)

suzy= 180-(90+30)= 180-120=60

((sin 90)/20)= ((sin 60)/y)

(1/20)= (0.8660/y)

Cross multiply

y= 0.8660*20

y= 17.3

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2 years ago

What is the answer to 3/7w-11=4/7w

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3 years ago

35. For the following exercises, given each set of information, find a linear equation satisfying the conditions, if possible.

Montano1993 [528]

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The linear equation for the line which passes through the points given as (-2,8) and $(4,6), is written in the point-slope form as $y=-\frac{1}{3} x-\frac{26}{3}$ .

Step-by-step explanation:

A condition is given that a line passes through the points whose coordinates are (-2,8) and (4,6).

It is asked to find the linear equation which satisfies the given condition.

Step 1 of 3

Determine the slope of the line.

The points through which the line passes are given as (-2,8) and (4,6). Next, the formula for the slope is given as,

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substitute $6 \& 8$ for $y_{2}$ and $y_{1}$ respectively, and 4&-2 for $x_{2}$ and $x_{1}$ respectively in the above formula. Then simplify to get the slope as follows, $m=\frac{6-8}{4-(-2)}$

$\begin{aligned}&m=\frac{-2}{6} \\&m=-\frac{1}{3}\end{aligned}$

Step 2 of 3

Write the linear equation in point-slope form.

A linear equation in point slope form is given as,

$y-y_{1}=m\left(x-x_{1}\right)$

Substitute $-\frac{1}{3}$ for m,-2 for $x_{1}$ , and 8 for $y_{1}$ in the above equation and simplify using the distributive property as follows, $y-8=-\frac{1}{3}(x-(-2))$\\ $y-8=-\frac{1}{3}(x+2)$\\ $y-8=-\frac{1}{3} x-\frac{2}{3}$$

Step 3 of 3

Simplify the equation further.

Add 8 on each side of the equation $y-8=-\frac{1}{3} x-\frac{2}{3}$ , and simplify as follows, $y-8+8=-\frac{1}{3} x-\frac{2}{3}+8$

$y=-\frac{1}{3} x-\frac{2+24}{3}$$\\ $$y=-\frac{1}{3} x-\frac{26}{3}$$

This is the required linear equation.

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2 years ago