$\text{Standard Score, z} =\dfrac{X-\mu}{\sigma} $ where:\\\\Mean Pulse rate, \mu =67.3$ beats per minute\\Standard Deviation, \sigma = 10.3$ beats per minute.\\$

For a male student who has a measured pulse rate of 52 beats per minute.

Raw Score, X =52 beats per minute.

Therefore:

$\text{Standard Score, z} =\dfrac{52-67.3}{10.3}\\z=-1.49$

Since the usual pulse rates are within 2 standard deviations of the mean, a z-score of -1.49 tells us that the selected student's pulse rate is within the usual pulse rates.

8 0

4 years ago

Can someone please help me solve this?

ra1l [238]

AC is congruent to itself
AC bisects angle BAD, so that angles BAC and DAC are congruent
Both angles B and D are right angles, so they are congruent

This means triangles BAC and DAC are a pair of angle-angle-side triangles, so they are congruent to one another. Corresponding parts of congruent triangles are congruent, so the line segments BC and DC are congruent and have the same length.

Then

$8n+2=2n+20\implies6n=18\implies n=3$

4 0

3 years ago