Answer:
There are no true solutions to the equation
Step-by-step explanation:
The equation is
y+1=√-2y-3
Find y
Square both sides
(y+1)^2=(√-2y-3)^2
y^2+2y+1= -2y-3
y^2+2y+1+2y+3=0
y^2+4y+4=0
Solve quadratic equation by factorisation
we have
(y+2)(y+2)=0
y=-2
Check
y+1=√-2y-3
-2+1=√-2(-2)-3
-1=√4-3
-1=√1
-1=1
This is not true
A possible coordinate could be 4.....
Ross would be the correct answer. To figure it out you would divide 27/3 which is 9 and then 49/7 which is 7. So 9>7.
