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3 years ago

13=2m+5 solve for m?

Mathematics

2 answers:

BlackZzzverrR [31]3 years ago

5 0

Answer:

I believe to answer to m would be 4

Step-by-step explanation:

Given knowing that 2m + 5 is equal to 13, you could always subtract to find m.

13 - 5 = 8

Given 8, we know that any number multiplying by 2 would have the answer of 8. You could divide 8 by 2 to find your missing variable.

8 ÷ 2 = 4

Which leaves you with 4, which means 4 is your missing variable.

m = 4

13 = 2(4) + 5

Vika [28.1K]3 years ago

3 0

Answer:

m=4

This is because you subtract 5 then divide it all by 2

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59.67÷11.1 what's the answer show me the work

Brilliant_brown [7]

Answer:

5.375676

change the divisor 11.1 to a whole number by moving the decimal point 1 placesa to the right. then move the decimal point in the dividend the same. then you have 596.7/111=5.375

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3 years ago

Please answer this question now

shtirl [24]

Answer:

76 degrees.

Step-by-step explanation:

Let as consider O is the center of the circle . So from the figure it is clear that

$\angle AOB=44^{\circ}$

$\angle COD=118^{\circ}$

By central angle theorem, central angle subtended by an arc is twice of inscribed angle of the same arc.

We know that, $\angle BAD=97^{\circ}$ and angle BOD is the central angle subtended by arc BD.

$\angle BOD=2\times \angle BAD$

$\angle BOD=2\times 97^{\circ}$

$\angle BOD=194^{\circ}$

Now,

$\angle BOD=\angle BOC+\angle COD$

$194^{\circ}=\angle BOC+118^{\circ}$

$194^{\circ}-118^{\circ}=\angle BOC$

$76^{\circ}=\angle BOC$

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Therefore, the measure of arc BC is 76 degrees.

5 0

3 years ago

What is the answers to this

mash [69]

Answers to what exactly?

3 0

3 years ago

Which of the following fractions has the same value as the decimal number 0.65?

boyakko [2]

Answer:

13/20

Step-by-step explanation:

To find this, divide 13 by 20 to get .65

Hope this helped!

4 0

3 years ago

What is the coefficient of x2y3 in the expansion of (2x + y)5?

Zigmanuir [339]

Option C:

The coefficient of $x^{2} y^{3}$ is 40.

Solution:

Given expression:

$(2 x+y)^{5}$

Using binomial theorem:

$(a+b)^{n}=\sum_{i=0}^{n}\left(\begin{array}{l}n \\i\end{array}\right) a^{(n-i)} b^{i}$

Here $a=2 x, b=y$

Substitute in the binomial formula, we get

$(2x+y)^5=\sum_{i=0}^{5}\left(\begin{array}{l}5 \\i\end{array}\right)(2 x)^{(5-i)} y^{i}$

Now to expand the summation, substitute i = 0, 1, 2, 3, 4 and 5.

$$=\frac{5 !}{0 !(5-0) !}(2 x)^{5} y^{0}+\frac{5 !}{1 !(5-1) !}(2 x)^{4} y^{1}+\frac{5 !}{2 !(5-2) !}(2 x)^{3} y^{2}+\frac{5 !}{3 !(5-3) !}(2 x)^{2} y^{3}$