At first glance the answer seems like 3
u should draw it out
Answer:
650
Step-by-step explanation:
651.606881968=P
round: 650
Answer:

Step-by-step explanation:
One is given the following equation;

The problem asks one to find the roots of the equation. The roots of a quadratic equation are the (x-coordinate) of the points where the graph of the equation intersects the x-axis. In essence, the zeros of the equation, these values can be found using the quadratic formula. In order to do this, one has to ensure that one side of the equation is solved for (0) and in standard form. This can be done with inverse operations;


This equation is now in standard form. The standard form of a quadratic equation complies with the following format;

The quadratic formula uses the coefficients of the quadratic equation to find the zeros this equation is as follows,

Substitute the coefficients of the given equation in and solve for the roots;

Simplify,

Therefore, the following statement can be made;

To solve this question you would first multiply all the dimensions of the pillar together. That would be:
2.5 x 2.5 x 12 = 75 square feet
Then you take the weight of the pillar and divide it by the amount of square feet:
12,000 / 75 = 160 pounds per square foot.