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3 years ago

1. Y=-2×+4 Complete the missing value in the solution to the equation (____,-2)

Mathematics

2 answers:

yuradex [85]3 years ago

8 0

Answer:3

Step-by-step explanation:

Ipatiy [6.2K]3 years ago

6 0

Answer:

x =2

Step-by-step explanation:

y = - 2 x + 4

0 = - 2 x + 4

x = 2

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Let F⃗ =2(x+y)i⃗ +8sin(y)j⃗ .

Alik [6]

Answer:

-42

Step-by-step explanation:

The objective is to find the line integral of $F$ around the perimeter of the rectangle with corners (4,0), (4,3), (−3,3), (−3,0), traversed in that order.

We will use <em>the Green's Theorem </em>to evaluate this integral. The rectangle is presented below.

We have that

$F(x,y) = 2(x+y)i + 8j \sin y = \langle 2(x+y), 8\sin y \rangle$

Therefore,

$P(x,y) = 2(x+y) \quad \wedge \quad Q(x,y) = 8\sin y$

Let's calculate the needed partial derivatives.

$P_y = \frac{\partial P}{\partial y} (x,y) = (2(x+y))'_y = 2\\Q_x =\frac{\partial Q}{\partial x} (x,y) = (8\sin y)'_x = 0$

Thus,

$Q_x -P_y = 0 -2 = - 2$

Now, by the Green's theorem, we have

$\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA = \int \limits_{-3}^{4} \int \limits_{0}^{3} (-2)\,dy\, dx \\ \\\phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-2y) \Big|_{0}^{3} \; dx\\ \phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-6)\; dx = -6x \Big|_{-3}^{4} = -42$

4 0

2 years ago

What is the least common factor of 60,66

Ilia_Sergeevich [38]

Answer:3

Step-by-step explanation: 60/6=10

66/6=11

60/3=20

66/3=22 you double the numbers of the quotient which halves the factor.

4 0

2 years ago

Please help ASAP and help me find what the value of x is

elixir [45]

Answer:

x=44

Step-by-step explanation:

33+103+x=180

136+x=180

x=44

6 0

3 years ago

Read 2 more answers

Help Mathematics. (:(:(:(:

kumpel [21]

Lawrence's is the correct answer. he put 3 plates on each box in both situations

8 0

2 years ago

Carl ran around the track 3 more times than Daria and 2 fewer times than Erin. When they were done they added up the number of l

Paul [167]

Answer:

Total laps = 10d

Step-by-step explanation:

Let c = Carl's laps

d = Daria's laps

e = Erin's laps

c = 3d

c = e/2

c + d + e = totals laps

We can insert 3d in place of c in the third equation

3d + d + e = total laps

Also, e/2 equals 3d

e/2 = 3d

Multiply both sides by 2

(e/2 = 3d)2

e = 6d

Insert the new e

3d + d + 6d = 10d = totals laps

3 0

2 years ago