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Solnce55 [7]
3 years ago
12

Each letter of the word GEOMETRICAL is written on a separate piece of paper and put in a bag. You pick a random letter from the

bag. What is the probability that it is a vowel?
Mathematics
1 answer:
zhuklara [117]3 years ago
7 0

Answer:

5/11

Step-by-step explanation:

Probability is the chance that something will happen. Basically, it answers the question of how many times an event will occur in a given number of opportunities.

In this example, the word "GEOMETRICAL" has 11 letters and 5 of them are vowels. They are: E, O, E, I, A. The probability of picking a vowel is 5/11. We could say that there are 5 out of 11 chances of a vowel to occur whenever a piece of paper is taken out of the bag.

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blagie [28]
You must first normalize this in order to use a Z-score table. To convert what you have into a Z score you must use this formula: (x- mean) /standard deviation. In your case (334-310)/12=2. So now you want the probability that a score is greater than 334, which in turn means you want P(Z>2)=1-P(Z<2)=1-.9772=0.0228=2.28%.
5 0
3 years ago
The arrivals of clients at a service firm in Santa Clara is a random variable from Poisson distribution with rate 2 arrivals per
ICE Princess25 [194]

Answer:

1.76% probability that in one hour more than 5 clients arrive

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

The arrivals of clients at a service firm in Santa Clara is a random variable from Poisson distribution with rate 2 arrivals per hour.

This means that \mu = 2

What is the probability that in one hour more than 5 clients arrive

Either 5 or less clients arrive, or more than 5 do. The sum of the probabilities of these events is decimal 1. So

P(X \leq 5) + P(X > 5) = 1

We want P(X > 5). So

P(X > 5) = 1 - P(X \leq 5)

In which

P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-2}*2^{0}}{(0)!} = 0.1353

P(X = 1) = \frac{e^{-2}*2^{1}}{(1)!} = 0.2707

P(X = 2) = \frac{e^{-2}*2^{2}}{(2)!} = 0.2707

P(X = 3) = \frac{e^{-2}*2^{3}}{(3)!} = 0.1804

P(X = 4) = \frac{e^{-2}*2^{4}}{(4)!} = 0.0902

P(X = 5) = \frac{e^{-2}*2^{5}}{(5)!} = 0.0361

P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.1353 + 0.2702 + 0.2702 + 0.1804 + 0.0902 + 0.0361 = 0.9824

P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9824 = 0.0176

1.76% probability that in one hour more than 5 clients arrive

8 0
3 years ago
Read 2 more answers
Find f(x)=x^2-x^3,find f(-10)
sergij07 [2.7K]

Answer:

f(-10) = 1,100

Step-by-step explanation:

f(-10) = (-10)^2 - (-10)^3

= 100 - (-1000)

= 1,100

3 0
3 years ago
Aaron, Bonny and Connor are playing a game with cards.
professor190 [17]

Let the number of cards Aaron has : A

Given :

⊕   Bonny has twice as many cards as Aaron

⊕   Connor has 6 cards more than Bonny

⊕   Total cards : 101

⇒  Number of cards Bonny has : 2A

⇒  Number of cards Connor has : 2A + 6

⇒   Aaron cards + Bonny cards + Connor cards = 101

⇒   A + 2A + 2A + 6 = 101

⇒   5A = 101 - 6

⇒   5A = 95

⇒   A = 19

<u>Answer</u> : Aaron has 19 Cards

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3 years ago
Jeff worked 4 2/3 hours in the morning and 3 3/4 hours in the afternoon. How many total hours did he work today?
Rainbow [258]
If you would like to know how many total hours did Jeff work today, you can calculate this using the following steps:

4 2/3 hours in the morning + 3 3/4 hours in the afternoon = 4 2/3 + 3 3/4 = 14/3 + 15/4 = 56/12 + 45/12 = (56 + 45) / 12 = 101/12 = 8 5/12 hours

Jeff worked 8 5/12 hours in total.
7 0
3 years ago
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