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joja [24]
3 years ago
12

Consider the following set of equations:

Mathematics
1 answer:
zzz [600]3 years ago
3 0
The first one 2x+4= 3x+1
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A rectangular flying carpet is 1 1/2 m wide and 2 m long what is the area of the carpet
d1i1m1o1n [39]

Hi there! :)

<u>Answer:</u>

The area of the carpet is <u>3m²</u>.


Step-by-step explanation:

First off, the formula to calculate the area of a rectangle is this: A = L × W

Where "A" is the area, "L" the length and "W" the width.

Now that you have that, replace all the information you know in the equation in order to find the value of "A", which is what we are looking for:

- Just keep in mind that 1 1/2 is the same thing as 1.5

- The term "wide" is used to give the "width"

- The term "long" is used to give the "length"


A = L × W

A = 2 × 1.5

<u>A = 3</u>


There you go! I really hope this helped, if there's anything just let me know! :)

4 0
3 years ago
PTG has side lengths of 18cm, 14cm, and 16cm which type of triangle is PTG
mihalych1998 [28]
I want to say it is an acute angel 
8 0
3 years ago
Read 2 more answers
-6x-4+5x=4<br> What is "x". Please show your work.
4vir4ik [10]

Answer:

first thing to do is combine like terms

now you would have -x-4=4

this is because you added -6x+5x

now you would add 4 to each side

now you would have-x=8

then you would divide the negative because x has to be positive

now you would have x= -8

that is your answer. if you any questions just ask :D

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Line segment 19 units long running from (x,0) ti (0, y) show the area of the triangle enclosed by the segment is largest when x=
Debora [2.8K]
The area of the triangle is

A = (xy)/2

Also,

sqrt(x^2 + y^2) = 19

We solve this for y.

x^2 + y^2 = 361

y^2 = 361 - x^2

y = sqrt(361 - x^2)

Now we substitute this expression for y in the area equation.

A = (1/2)(x)(sqrt(361 - x^2))

A = (1/2)(x)(361 - x^2)^(1/2)

We take the derivative of A with respect to x.

dA/dx = (1/2)[(x) * d/dx(361 - x^2)^(1/2) + (361 - x^2)^(1/2)]

dA/dx = (1/2)[(x) * (1/2)(361 - x^2)^(-1/2)(-2x) + (361 - x^2)^(1/2)]

dA/dx = (1/2)[(361 - x^2)^(-1/2)(-x^2) + (361 - x^2)^(1/2)]

dA/dx = (1/2)[(-x^2)/(361 - x^2)^(1/2) + (361 - x^2)/(361 - x^2)^(1/2)]

dA/dx = (1/2)[(-x^2 - x^2 + 361)/(361 - x^2)^(1/2)]

dA/dx = (-2x^2 + 361)/[2(361 - x^2)^(1/2)]

Now we set the derivative equal to zero.

(-2x^2 + 361)/[2(361 - x^2)^(1/2)] = 0

-2x^2 + 361 = 0

-2x^2 = -361

2x^2 = 361

x^2 = 361/2

x = 19/sqrt(2)

x^2 + y^2 = 361

(19/sqrt(2))^2 + y^2 = 361

361/2 + y^2 = 361

y^2 = 361/2

y = 19/sqrt(2)

We have maximum area at x = 19/sqrt(2) and y = 19/sqrt(2), or when x = y.
3 0
3 years ago
How do you find surface area ? i don't remember. also new friends :) ?
Montano1993 [528]

Answer:

be my bestie

Step-by-step: The surface area is the number of square units that fit into the square. As shown in the picture, the surface area of this square is 16 total square units. With a rectangle and square we can also get the surface area by multiplying width (W) x length (L).tep explanation:

4 0
3 years ago
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