Question

A bag contains 4 red marbles, 7 blue marbles, and 6 green marbles. What is the probability of choosing a blue marble when one marble is drawn?

Answer 1

Answer: 7/17
So there are 7 blue marbles and there are 17 marbles in total.
That means the probability of picking one blue marble is 7/17

Answer 2

Answer:

$\frac{7}{17}$

Step-by-step explanation:

We have been given that a bag contains 4 red marbles, 7 blue marbles, and 6 green marbles. We are asked to find the probability of choosing a blue marble when one marble is drawn.

$\text{Probability}=\frac{\text{Number of favorable outcomes}}{\text{Total number of possible outcomes}}$

$\text{Probability}=\frac{7}{4+7+6}$

$\text{Probability}=\frac{7}{17}$

Therefore, the probability of choosing a blue marble is $\frac{7}{17}$.