All categories

3 years ago

Determine whether the given value of the variable is a solution of the equation. 1/3c = 3/8; c = 3/4

Mathematics

2 answers:

Sonja [21]3 years ago

6 0

It doesn't. One third multiplied by three fourths is one fourth or .25

Gennadij [26K]3 years ago

5 0

It is not a solution

You might be interested in

For which inequality is x=5 a solution?

chubhunter [2.5K]

Answer:

Step-by-step explanation:

Just replaced the x with 5 and check if it is a true statement

8 0

3 years ago

Assume f(x) = -2x+8 and g(x) = 5x. What is the value of (f o g)(3)?

makkiz [27]

Answer: C

Step-by-step explanation:

(fog)(3) is the same as finding f(g(3)). To solve, we first need to solve g(3). then, we solve for f(g(3)).

g(3)=5(3) [multiply]

g(3)=15

Now, we plug in 15 into f(x).

f(g(3))=-2(15)+8 [multiply]

f(g(3))=-30+8 [add]

f(g(3))=-22

Now, we know that C is the correct answer.

4 0

3 years ago

Let F=(2x,2y,2x+2z)F=(2x,2y,2x+2z). Use Stokes' theorem to evaluate the integral of FF around the curve consisting of the straig

Brilliant_brown [7]

Stokes' theorem equates the line integral of $\vec F$ along the curve to the surface integral of the curl of $\vec F$ over any surface with the given curve as its boundary. The simplest such surface is the triangle with vertices (1,0,1), (0,1,0), and (0,0,1).

Parameterize this triangle (call it $T$ ) by

$\vec s(u,v)=(1-v)((1-u)(1,0,1)+u(0,1,0))+v(0,0,1)$

$\vec s(u,v)=((1-u)(1-v),u(1-v),1-u+uv)$

with $0\le u\le1$ and $0\le v\le1$ . Take the normal vector to $T$ to be

$\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}=(0,1-v,1-v)$

Divide this vector by its norm to get the unit normal vector. Note that this assumes a "positive" orientation, so that the boundary of $T$ is traversed in the counterclockwise direction when viewed from above.

Compute the curl of $\vec F$ :

$\vec F=(2x,2y,2x+2z)\implies\mathrm{curl}\vec F=(0,-2,0)$

Then by Stokes' theorem,

$\displaystyle\int_{\partial T}\vec F\cdot\mathrm d\vec r=\iint_T\mathrm{curl}\vec F\cdot\mathrm d\vec S$

where

$\mathrm d\vec S=\dfrac{\frac{\partial\vec s}{\partial u}\times\frac{\partial\vec s}{\partial v}}{\left\|\frac{\partial\vec s}{\partial u}\times\frac{\partial\vec s}{\partial v}\right\|}\,\mathrm dS$

$\mathrm d\vec S=\dfrac{\frac{\partial\vec s}{\partial u}\times\frac{\partial\vec s}{\partial v}}{\left\|\frac{\partial\vec s}{\partial u}\times\frac{\partial\vec s}{\partial v}\right\|}\left\|\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

$\mathrm d\vec S=\left(\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}\right)\,\mathrm du\,\mathrm dv$

The integral thus reduces to

$\displaystyle\int_0^1\int_0^1(0,-2,0)\cdot(0,1-v,1-v)\,\mathrm du\,\mathrm dv=\int_0^12(v-1)\,\mathrm dv=\boxed{-1}$

3 0

3 years ago

Write the equation of the line that passes through the points (−9,−6) and (−1,6). Put your answer in fully reduced point-slope f

Scrat [10]

Answer:

y+6=3/2(x+9)

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(6-(-6))/(-1-(-9))

m=(6+6)/(-1+9)

m=12/8

simplify

m=3/2

y-(-6)=3/2(x-(-9))

y+6=3/2(x+9)

7 0

3 years ago

What percentage of a dollar is the value of 5 quarters and 1 dime

slega [8]

Answer:

135%

Step-by-step explanation:

The quarters percentage is 125% and the dime is 10% and that equals 135%

3 0

3 years ago