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yKpoI14uk [10]
3 years ago
7

Matter appears to be conserved in chemical reactions but not in nuclear reactions because:

Chemistry
2 answers:
Vlad [161]3 years ago
8 0
I think the best answer is B. Even this is the broadest case for the Conservation of matter and the one for Energy, the only way this can be applied is in nuclear rxns.
kozerog [31]3 years ago
5 0

Answer:  The law of conservation of mass-energy applies only to nuclear reactions

Explanation:   In nuclear reactions, mass and energy both are conserved but not in a simple manner.

The nuclear reactions are known to violate the law of conservation of mass because the rest mass is converted and appears in the form of kinetic energy.

But the toral energy remains the same.

Thus it can be said that the sum of mass and energy are conserved n the nuclear reactions.

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A airliner has an internal pressure of 1.00 ATM and temperatures of 25°C at take off if the temperature of the airlines routes t
Georgia [21]

Answer:

Explanation:

Using Gay lussac's law equation as follows;

P1/T1 = P2/T2

7 0
3 years ago
What is the structure of an<br> atom?
tresset_1 [31]

Atoms consist of three basic particles: protons, electrons, and neutrons. The nucleus (center) of the atom contains the protons (positively charged) and the neutrons (no charge). The outermost regions of the atom are called electron shells and contain the electrons (negatively charged).

8 0
3 years ago
What is the mass of 0.015 moles of NaOH?
JulsSmile [24]

Answer:

Mass = 0.6 g

Explanation:

Given data:

Moles of NaOH = 0.015 mol

Mass of NaOH = ?

Solution:

Number of moles = mass/ molar mass

by rearranging this formula,

Mass = number of moles × molar mass

Molar mass of NaOH is 40 g/mol

by putting values,

Mass = 0.015 mol × 40 g/mol

Mass = 0.6 g

3 0
3 years ago
A 10.1 g sample of NaOH is dissolved in 250.0 g of water in a coffee-cup calorimeter. The temperature increases from 23.0 °C to
givi [52]

Hey there!:

moles of NaOH = 10.1 / 40 = 0.2525

heat  = ΔH   x  moles

= 44.4 x 0.2525

= 11.21 kJ

total mass  = 10.1 + 250 = 260.1 g

Q  = m Cp dT

11211    = 260.1 x  4.18 x dT

dT  = 10.3

T2  = 10.3 + 23  = 33.3 °C

temperature = 33.3 ºC°

Hope this helps!

6 0
3 years ago
Read 2 more answers
Consider the following chemical equilibrium:
jok3333 [9.3K]

Answer:

Kc = [CH₄] / [H₂]²

Kp = [CH₄] / [H₂]² * (0.082*T)^-1

Explanation:

Equilibrium constant, Kc, is defined as the ratio of the concentrations of the products over the reactants. Also, each concentration of product of reactant is powered to its coefficient.

<em>Pure solids and liquids are not taken into account in an equilibrium</em>

Thus, for the reaction:

C(s)+ 2H₂(g) ⇌ CH₄(g)

Equilibrium constant is:

<h3>Kc = [CH₄] / [H₂]²</h3>

Now, using the formula:

Kp = Kc* (RT)^Δn

<em>Where R is gas constant (0.082atmL/molK), T is the temperature of the reaction and Δn is difference in coefficients of gas products - coefficients of gas reactants (1 - 2= -1)</em>

Replacing:

<h3>Kp = [CH₄] / [H₂]² * (0.082*T)^-1</h3>

<em />

4 0
3 years ago
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