Answer : The net ionic equation will be,
Explanation :
In the net ionic equations, we are not include the spectator ions in the equations.
Spectator ions : The same number of ions present on reactant and product side which do not participate in a reactions.
The given balanced ionic equation will be,
The ionic equation in separated aqueous solution will be,
In this equation, 
are the spectator ions.
By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.
The net ionic equation will be,
Answer:
A little boy is playing with a plastic water bottle. He blows air into the bottle to make a whistling sound. Then, he wedges a plastic ball into the bottle to make a rattle. But the ball is too big—it gets stuck in the mouth of the bottle! The little boy panics and runs to his big brother for help.
Luckily, his older brother just studied the principle of Boyle's law. Based on what he learned, how will he get the ball out of the bottle?
by placing the bottle in the freezer to decrease the mass of the air inside the bottle
by pushing down on the bottle to decrease the temperature of the air in the bottle
by placing the bottle in the freezer to increase the air pressure inside the bottle
by pushing down on the bottle to increase the air pressure inside the bottle?
Explanation:
You will need to heat the bottom of the bottle to make gas build up than the ball will pop out.
I dont know what subject is this
<span>294400 cal
The heating of the water will have 3 phases
1. Melting of the ice, the temperature will remain constant at 0 degrees C
2. Heating of water to boiling, the temperature will rise
3. Boiling of water, temperature will remain constant at 100 degrees C
So, let's see how many cal are needed for each phase.
We start with 320 g of ice and 100 g of liquid, both at 0 degrees C. We can ignore the liquid and focus on the ice only. To convert from the solid to the liquid, we need to add the heat of fusion for each gram. So multiply the amount of ice we have by the heat of fusion.
80 cal/g * 320 g = 25600 cal
Now we have 320 g of ice that's been melted into water and the 100 g of water we started with, resulting in 320 + 100 = 420 g of water at 0 degrees C. We need to heat that water to 100 degrees C
420 * 100 = 42000 cal
Finally, we have 420 g of water at the boiling point. We now need to pump in an additional 540 cal/g to boil it all away.
420 g * 540 cal/g = 226800 cal
So the total number of cal used is
25600 cal + 42000 cal + 226800 cal = 294400 cal</span>
