Answer:
[ N₂(g) ] = 0.016 M
Explanation:
N₂(g) + 3 H₂(g) ↔ 2 NH₃(g)
The equilibrium constant for the above reaction , can be written as the product of the concentration of product raised to the power of stoichiometric coefficients in a balanced equation of dissociation divided by the product of the concentration of reactant raised to the power of stoichiometric coefficients in the balanced equation of dissociation .
Hence ,
Kc = [ NH₃ (g) ]² / [ N₂(g) ] [ H₂(g) ]³
From the question ,
[ NH₃ (g) ] = 0.5 M
[ N₂(g) ] = ?
[ H₂(g) ] = 2.0 M
Kc = 2
Now, putting it in the above equation ,
Kc = [ NH₃ (g) ]² / [ N₂(g) ] [ H₂(g) ]³
2 = [ 0.5 M ]² / [ N₂(g) ] [ 2.0 M ]³
[ N₂(g) ] = 0.016 M .
Answer:
Co2,so2
Explanation:
Hybridization is the mixing of atomic orbitals to form new hybrid orbitals.
Molecule shapes arise from how many hybrid orbitals the central atom uses and how they are arranged.
Don't read the all this but don't forget to leave a ❤
Hi,
You didn't mention what "the following" were - please add additional information so the problem can be solved.
Answer:
75.0%
Explanation:
Data obtained from the question. This includes the following:
Actual yield = 6.13g
Theoretical yield = 8.17g
Percentage yield =...?
The percentage yield can be obtain by using the following formula:
Percentage yield = Actual yield /Theoretical yield x 100
Percentage yield = 6.13/8.17 x 100
Percentage yield = 75.0%
Therefore, the percentage yield of water from the reaction above is 75.0%
