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BaLLatris [955]
3 years ago
5

Density is ___ to pressure

Chemistry
1 answer:
Ann [662]3 years ago
5 0
Proportional to pressure
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How does a concave lens differ from a convex lens? A) A convex lens is another way to describe a plane mirror; a concave lens is
elixir [45]
<h3><u>Answer;</u></h3>

C) A convex lens has a thick center and thin edges; a concave lens has a thin center and thicker edges.

<h3><u>Explanation;</u></h3>
  • Convex lens refers to the lens which merges the light rays at a particular point, that travels through it, while a concave lens can be identified as the lens which disperses the light rays around, that hits the lenses.
  • A convex lens is thicker at the center, as compared to its edges, while a concave lens is thinner at the center as compared to its edges.
  • A concave lens is thicker at the edges than in the middle and spreads light rays apart producing an image smaller than the actual object. A convex lens on the other hand, is thinner at the edges and thicker towards the center, that is they are bent towards a central point.
7 0
3 years ago
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Charlie is balancing an equation. She has identified the atoms and counted the number of each in the reactants and products. Wha
Alecsey [184]
The answer to your question is Coefficients. 

*Hope this helps you! Feel free to message me if you have any further questions. Have a nice day! :)*
8 0
3 years ago
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A 2.950×10−2 M solution of glycerol (C3H8O3) in water is at 20.0∘C. The sample was created by dissolving a sample of C3H8O3 in w
11111nata11111 [884]

Answer:

The molality of the glycerol solution is 2.960×10^-2 mol/kg

Explanation:

Number of moles of glycerol = Molarity × volume of solution = 2.950×10^-2 M × 1 L = 2.950×10^-2 moles

Mass of water = density × volume = 0.9982 g/mL × 998.7 mL = 996.90 g = 996.90/1000 = 0.9969 kg

Molality = number of moles of glycerol/mass of water in kg = 2.950×10^-2/0.9969 = 2.960×10^-2 mol/kg

7 0
3 years ago
A chemistry student is given the task of analyzing the three unknown samples in the previous question. Compare the densities fro
OLEGan [10]

Answer:

It’s B

Explanation:

6 0
3 years ago
P4O10(s) = -3110 kJ/mol H2O(l) = -286 kJ/mol H3PO4(s) = -1279 kJ/mol Calculate the change in enthalpy for the following process:
mash [69]

Answer:

-290KJ/mol

Explanation:

ΔHrxn = ΔHproduct - ΔHreactant

ΔHrxn= 4ΔHH3PO4 - {6ΔHH2O + ΔHP4O10}

ΔHrxn = 4(-1279) - [6(-286) - 3110]

= -5116 -(-1716-3110)

= -5116-(-4826)

= -5116 + 4826 = -290KJ/mol

6 0
3 years ago
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