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BaLLatris [955]
3 years ago
5

Density is ___ to pressure

Chemistry
1 answer:
Ann [662]3 years ago
5 0
Proportional to pressure
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How do food chains and food webs interact in an ecosystem
miss Akunina [59]

Answer:

There are a great many feeding relationships in any ecosystem, but energy always flows from primary producers to various consumers. These feeding relationships are represented by food chains and food webs. A food chain is a sequence in which organisms transfer energy by eating and being eaten.

Explanation:

7 0
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Why does water wet glass and not mercury​
trapecia [35]
Mercury probably isn’t as adhesive as water
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3 years ago
A 78 g of Aluminium bar place in water. The initical water level was 132 ml and the final water level was 144 ml. Find the Volum
Effectus [21]
The volume is 12 mL (0.012 L)

Before the aluminum was added, the water reached 132mL. After it was added, it reached 144. That means the Aluminum takes up (144-132)= 12mL of space.

The density = mass/volume. If the aluminum bar has a mass of 78g and volume of 0.012L, 78/0.012=6,500 g/L
8 0
3 years ago
A sample of an unknown liquid has a volume of 30.0 mL and a mass of 6 g. What is its density? please Show your work or explain h
Leno4ka [110]

The density of the liquid is 0.2 g/mL.

The mass of the liquid is 6 g.

The volume of the liquid is 30.0 mL.

Density = mass/volume = 6 g/30.0 mL = 0.2 g/mL

3 0
3 years ago
Consider the following multistep reaction:
chubhunter [2.5K]

The question is incomplete, here is the complete question:

Consider the following multistep reaction:

C+D⇌CD (fast)

CD+D→CD₂ (slow)

CD₂+D→CD₃ (fast)

C+3D→CD₃

Based on this mechanism, determine the rate law for the overall reaction.

<u>Answer:</u> The rate law for the reaction is \text{Rate}=k'[C][D]^2

<u>Explanation:</u>

Rate law is the expression which is used to express the rate of the reaction in terms of the molar concentration of reactants where each term is raised to the power their stoichiometric coefficient respectively from a balanced chemical equation.

In a mechanism of the reaction, the slow step in the mechanism determines the rate of the reaction.

For the given chemical reaction:

C+3D\rightarrow CD_3

The intermediate reaction of the mechanism follows:

<u>Step 1:</u>  C+D\rightleftharpoons CD;\text{ (fast)}

<u>Step 2:</u>  CD+D\rightarrow CD_2;\text{(slow)}

<u>Step 3:</u>  CD_2+D\rightarrow CD_3;\text{(fast)}

As, step 2 is the slow step. It is the rate determining step

Rate law for the reaction follows:

\text{Rate}=k[CD][D]           ......(1)

As, [CD] is not appearing as a reactant in the overall reaction. So, we apply steady state approximation in it.

Applying steady state approximation for CD from step 1, we get:

K=\frac{[CD]}{[C][D]}

[CD]=K[C][D]

Putting the value of [CD] in equation 1, we get:

\text{Rate}=k.K[C][D]^2\\\\\text{Rate}=k'[C][D]^2  

Hence, the rate law for the reaction is \text{Rate}=k'[C][D]^2

5 0
3 years ago
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