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ololo11 [35]
3 years ago
8

What is the number of moles of 27.6 grams of lithium

Chemistry
1 answer:
Leya [2.2K]3 years ago
6 0
Lithium's atomic weight is 6.94 g/mol.

27.6 g Li (\frac{mol}{6.94 g}) = 3.98 mol Li

Need anything else?

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Write a balanced net ionic equation for the following double replacement reaction
shtirl [24]

Answer:

Ba²⁺(aq) + SO₄²⁻(aq) ⟶ BaSO₄(s)  

Explanation:

There are three steps you must follow. You must write the:

  • Molecular equation
  • Ionic equation
  • Net ionic equation

A. Molecular equation

BaCl₂(aq) + Na₂SO₄(aq) ⟶ BaSO₄(s) + 2NaCl(aq)

B. Ionic equation

You write all the soluble substances as ions.

Ba²⁺(aq) + 2Cl⁻(aq) + 2Na⁺(aq) + SO₄²⁻(aq) ⟶ BaSO₄(s) + 2Na⁺(aq) + 2Cl⁻(aq)

C. Net ionic equation

To get the net ionic equation, you cancel the ions that appear on each side of the ionic equation.

Ba²⁺(aq) + <u>2Cl⁻(aq) </u>+ <u>2Na⁺(aq</u>) + SO₄²⁻(aq) ⟶ BaSO₄(s) + <u>2Na⁺(aq)</u> + <u>2Cl⁻(aq) </u>

The net ionic equation is

Ba²⁺(aq) + SO₄²⁻(aq) ⟶ BaSO₄(s)  

3 0
3 years ago
Heated bricks or blocks of iron were used long ago to warm beds. A 1.49 -kg block of iron heated to 155 Celsius would release ho
AlekseyPX
Specific heat capacity= Quantity of heat/massxΔT
Shc of iron (constant)= 0.4494J/³C for 1g
1.49kg=1490g
Q=1490x(22-155)x0.4494
Q=<span>89057.598J</span>
6 0
3 years ago
Find the mass of 5.82 mol of MgCl2. Round to the nearest tenth.
Oksana_A [137]

Answer:

554.13 grams

Explanation:

8 0
3 years ago
How might a molecule with two strong bond dipoles have no molecular dipole at all?
Reil [10]
 A molecule with two strong bond dipoles can have no molecular dipole if the bond dipoles cancel each other out by pointing in exactly opposite directions. For example, in carbon dioxide (a linear molecule), the carbon-oxygen bonds have a <span>large dipole moment. However, because one dipole points to the left and the other to the right the dipole is cancelled.</span>
5 0
3 years ago
Carbon-14 has a half-life of 5,730 years. How long will it take for 112. 5 g of a 120. 0-g sample to decay radioactively? 5,730
vichka [17]

The time taken by Carbon-14 to decay radioactively from 120g to 112.5g is 22,920 years.

<h3>How do we calculate the total time of decay?</h3>

Time required for the whole radioactive decay of any substance will be calculated by using the below link:

T = (n)(t), where

  • t = half life time = 5730 years
  • n = number of half life required for the decay

Initial mass of Carbon-14 = 120g

Final mass of Carbon-14 = 112.5g

Left mass = 120 - 112 = 7.5g

Number of required half life for this will be:

  • 1: 120 → 60
  • 2: 60 → 30
  • 3: 30 → 15
  • 4: 15 → 7.5

4 half lives are required, now on putting values we get

T = (4)(5730) = 22,920 years

Hence required time for the decay is 22,920 years.

To know more about radioactive decay, visit the below link:

brainly.com/question/24115447

#SPJ1

3 0
2 years ago
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