For the reaction BaSO3 (s) ↔ BaO (s) + SO2 (g), the equilibrium constant is 0.345 M. What is the concentration of SO2 at equilib
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Answer:
m = 671 grams
Explanation:
Given that,
No of moles, n = 4.9
Molar mass of Barium, M = 137 g
Mass divided by molar mass is equal to no of moles. It can be given by the formula as follows :
or
m = 671 grams
So, the total mass of the sample of Barium is 671 grams.