The molar mass of Li->7g/mol
If 1mol of Li is 7g/mol
1.50mol of Li would be 10.5g/mol
Answer:
20L is the new volume
Explanation:
In this case, moles and T° from the gas remain constant. This is the formula we must apply, to solve this:
P₁ . V₁ = P₂ . V₂
5 atm . 10 L = P₂ . 2.5L
P₂ = (5 atm . 10 L) / 2.5L →20L
Answer:
22.01J/Kmol
Explanation:
The parameters given in this question are;
Enthalpy (H) = 6.01 kJ/mol.
Number of moles = 1
Entropy change (S) = ?
The formular relationship between entropy and enthalpy is given as;
ΔS=ΔH/T
Temperature for water at freezing point = 0C + 273 = 273 K (converting to Kelvin)
ΔS = 6.01/273
ΔS = 0.0220kJ/Kmol
ΔS = 0.02201 * 1000 = 22.01J/Kmol
Answer:
One gram of carbon dioxide contains 13.6 x 10²¹ number of molecules.
Explanation:
