The solution is as follows:
K = [Partial pressure of isoborneol]/[Partial pressure of borneol] = 0.106
The molar mass of isoborneol/borneol is 154.25 g/mol
Mol isoborneol = 15 g/154.25 = 0.0972 mol
Mol borneol = 7.5 g/154.25 = 0.0486 mol
Use the ICE approach
borneol → isoborneol
I 0.0972 0.0486
C -x +x
E 0.0972 - x 0.0486 + x
Total moles = 0.1458
Using Raoult's Law,
Partial Pressure = Mole fraction*Total Pressure
[Partial pressure of isoborneol] = [(0.0972-x)/0.1458]*P
[Partial pressure of borneol] = [(0.0486+x/0.1458)]*P
0.106 = [(0.0972-x)/0.1458]*P/ [(0.0486+x/0.1458)]*P
Solving for x,
x = 0.0832
Thus,
<em>Mol fraction of borneol = (0.0486+0.0832)/0.1458 = 0.904</em>
<em>Mol fraction of isoborneol = (0.0972-0.0832)/0.1458 = 0.096</em>
Answer:
increase the rate of reaction.
Explanation:
For each of the situations below, state whether it describes erosion, weathering, or possibly both.
Answer:
Erosion
Explanation:
The blowing away of the top layer of the soil at a Michigan farm is best described as scenario that shows wind erosion.
Erosion is the removal of the top layer of the earth on which plant grows. In short is the washing away of soil by stream or blowing away by wind.
When soil is blow away, it is a pure case of erosion. The process of erosion usually follows weathering or sometime occurs together with it.
Weathering is the physical disintegration and chemical decomposition of rocks to form sediments and soils.
Often times, the process of weathering and erosion occurs together. It is loose weathering products that are carried away during erosion.
In the soil layer at Michigan, the process of erosion by wind is current taking place by ablation.
The letter only has reflection symmetry, if you rotated it it would look the same.
Answer:
Approximately 1.9 kilograms of this rock.
Explanation:
Relative atomic mass data from a modern periodic table:
To answer this question, start by finding the mass of Pb in each kilogram of this rock.
89% of the rock is . There will be 890 grams of in one kilogram of this rock.
Formula mass of :
.
How many moles of formula units in that 890 grams of ?
.
There's one mole of in each mole of . There are thus of in one kilogram of this rock.
What will be the mass of that of ?
.
In other words, the in 1 kilogram of this rock contains of lead .
How many kilograms of the rock will contain enough to provide 1.5 kilogram of ?
.