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topjm [15]
3 years ago
12

You have 104 apples. There are 8 bags full of the same amount of apples. How many apples are in each bag?

Mathematics
1 answer:
Irina-Kira [14]3 years ago
6 0
13 in each bag........
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If it takes 2 scoops of flour to make 16 cookies how many scoops of flour does it take to make 40
lisov135 [29]

Answer:

5

Step-by-step explanation:

40 divided by 16 = 2.5

2*2.5=5

3 0
4 years ago
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<img src="https://tex.z-dn.net/?f=%5Cqquad%5Chuge%5Cunderline%7B%5Cboxed%7B%5Csf%20%5C%3A%20Question%7D%7D" id="TexFormula1" tit
vovikov84 [41]

So here's gives that

total weight of 25 bags = 50 x 25

= 1250

total cost of 25 bags weighing 50 kg is = 15000

cost of 1 kg = 15000 ÷ 1250 = 12

now total weight of 15 bags weighing 30 kg = 450

cost per kg = 12

cost of 15 bags weighing 30 each = 450 x 12

Answer = 5400 rupees.

5 0
2 years ago
8 less than the product of 9 and a number is 15
Shkiper50 [21]
8-9n=15 I believe
At least I hope
4 0
3 years ago
Read 2 more answers
The two lines represent the amount of water, over time in two tanks that are the same size. Which container is filling more slow
Brut [27]
B is slowly and A is filling more quickly because the amount of water increases during a smaller period of time.
6 0
3 years ago
Point G is the centroid of the right △ABC with m∠C=90° and m∠B=30°. Find AG if CG=4 ft.
o-na [289]

Answer: \text{Length of AG=}\frac{2\sqrt{63}}{3}

Explanation:  

Please follow the diagram in attachment.  

As we know median from vertex C to hypotenuse is CM  

\therefore CM=\frac{1}{2}AB

We are given length of CG=4  

Median divide by centroid 2:1  

CG:GM=2:1  

Where, CG=4

\therefore GM=2 ft

Length of CM=4+2= 6 ft  

\therefore CM=\frac{1}{2}AB\Rightarrow AB=12

In \triangle ABC, \angle C=90^0

Using trigonometry ratio identities  

AC=AB\sin 30^0\Rightarrow AC=6 ft

BC=AB\cos 30^0\Rightarrow BC=6\sqrt{3} ft  

CN=\frac{1}{2}BC\Rightarrow CN=3\sqrt{3} ft

In \triangle CAN, \angle C=90^0  

Using pythagoreous theorem  

AN=\sqrt{6^2+(3\sqrt{3})^2\Rightarrow \sqrt{63}

Length of AG=2/3 AN

\text{Length of AG=}\frac{2\sqrt{63}}{3} ft


5 0
3 years ago
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