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4 years ago

What is the center and radius of the circle (x+4)^2+(y+6)^2=64

Mathematics

1 answer:

meriva4 years ago

5 0

Answer:

Step-by-step explanation:

hello :

the center is : (-4 , -6) and radius 8

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A company that makes pencils realized that 2 out of every 25 pencils were defective. How many pencils out of 200 will be defecti

levacccp [35]

2 X
— • — Cross multiply
25 200

25x 400
—— —— Divide
25 25

16

Out of 200, 16 pencils will be defective

6 0

3 years ago

Use the Green's Theorem to calculate the work done by the field [ F (x, y) = -3y^5 i + 5y^2x^3 j ] to move a particle along the

lianna [129]

$\displaystyle\int_C\mathbf F\cdot\mathrm d\mathbf r=\iint_R\left(\frac{\partial(5y^2x^3)}{\partial x}-\frac{\partial(-3y^5)}{\partial y}\right)\,\mathrm dx\,\mathrm dy$

$\dfrac{\partial(5y^2x^3)}{\partial x}=15y^2x^2$
$\dfrac{\partial(-3y^5)}{\partial y}=-15y^2$

$=\displaystyle\int_{x=-2}^{x=2}\int_{y=-\sqrt{4-x^2}}^{y=\sqrt{4-x^2}}15y^2(x^2+1)\,\mathrm dy\,\mathrm dx$

Converting to polar coordinates, the integral is equivalent to

$=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=2}15r^3\sin^2\theta(r^2\cos^2\theta+1)\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle15\int_0^{2\pi}\int_0^2\left(\frac{r^5}4\sin^22\theta+r^3\sin^2\theta\right)\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle\frac{15}4\left(\int_0^2r^5\,\mathrm dr\right)\left(\int_0^{2\pi}\sin^22\theta\,\mathrm d\theta\right)+15\left(\int_0^2r^3\,\mathrm dr\right)\left(\int_0^{2\pi}\sin^2\theta\,\mathrm d\theta\right)$
$=100\pi$

6 0

3 years ago

Solve the inequality 2x – 22 < -8.

Strike441 [17]

2x - 22 < -8

Add 22 to both sides

2x < 14

Divide both sides by 2

X < 7

6 0

3 years ago

Read 2 more answers

For the past three months Grace used her cell phone for 43 minutes 62 minutes and 57 minutes how many minutes would you have to

RSB [31]

Answer:

Grace should use her phone for 58 minutes to maintain an average of 55 minutes.

Step-by-step explanation:

Usage of first month = 43 minutes

Second month = 62 minutes

Third Minutes = 57 minutes

Let, the usage of fourth month = k minutes

Mean of the data = 5 minutes

Now, Average of a Data = $\frac{\textrm{Sumof observations}}{\textrm{Total number of observations}}$

⇒ $55 = \frac{43 + 62 + 57 + k}{4}$

or, 55 x 4 = 162 + k

⇒ 220 - 162 = k

or, k = 58 minutes

So, Grace should use her phone for 58 minutes to maintain an average of 55 minutes.

5 0

3 years ago

Hi! I know this is super random but I'm genuinely confused

Ivan

Answer:

Well, usually tapeworms are usually found in the intestines. Male giraffes can have intenstines as long as 230 feet! Also, tapeworms are usually all bunched up, they aren't straight and stretched out in the intestines.

Hope this helped!

7 0

3 years ago