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ipn [44]
3 years ago
9

20x+x-2=4 rational equation​

Mathematics
2 answers:
laila [671]3 years ago
8 0

Answer:

x = 2/7

Step-by-step explanation:

Step 1: Write equation

20x + x - 2 = 4

Step 2: Solve for <em>x</em>

  1. <u>Combine like terms:</u> 21x - 2 = 4
  2. <u>Add 2 to both sides:</u> 21x = 6
  3. <u>Divide both sides by 21:</u> x = 6/21
  4. <u>Simplify:</u> x = 2/7

Step 3: Check

<em>Plug in x to verify it's a solution.</em>

20(2/7) + 2/7 - 2 = 4

40/7 + 2/7 - 2 = 4

42/7 - 2 = 4

6 - 2 = 4

4 = 4

vitfil [10]3 years ago
7 0

Answer:

x = 2/7

Step-by-step explanation:

Collect like terms:

20x + x = 21x ----> 21x - 2= 4

Move the constant to the right hand side and change the sign of the constant:

21x = 4 + 2

Calculate:

21x = 4 + 2 ---> 21x = 6

Divide both sides by 21:

21/21 and 6/21 = 2/7

Solution:

x = 2/7 or x= 0.285714

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Answer:

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Given the set of vertices, determine whether parallelogram ABCD is a rhombus, rectangle or square. List all that apply. A(7,-4),
Sloan [31]

Given:

Vertices of a parallelogram ABCD are A(7,-4), B(-1,-4), C(-1,-12), D(7, -12).

To find:

Whether the parallelogram ABCD is a rhombus, rectangle or square.

Solution:

Distance formula:

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Using distance formula, we get

AB=\sqrt{(-4-(-4))^2+(-1-7)^2}

AB=\sqrt{(-4+4)^2+(-8)^2}

AB=\sqrt{0+64}

AB=8

Similarly,

BC=\sqrt{(-1-(-1))^2+(12-(-4))^2}=8

CD=\sqrt{(7-(-1))^2+(-12-(-12))^2}=8

AD=\sqrt{(7-7)^2+(-12-(-4))^2}=8

All sides of parallelogram are equal.

AC=\sqrt{(-1-7)^2+(-12-(-4))^2}=8\sqrt{2}

BD=\sqrt{(7-(-1))^2+(-12-(-4))^2}=8\sqrt{2}

Both diagonals are equal.

Since, all sides are equal and both diagonals are equal, therefore, the parallelogram ABCD is a square.

We know that, a square is special case of rectangles and rhombus.

So, parallelogram ABCD is a rhombus, rectangle or square. Therefore, the correct option is c.

7 0
3 years ago
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