when you use all prime, non-one numbers for b and c, it cannot be factored most of the time
example
1x^2+7x+5
a=1
b=7
c=5
x=
x=
x=
x=
x=
or 
example
1x^2+7x+5
a=1
b=7
c=5
x=
x=
x=
x=
x=
Can someone please help me with question 1, I will mark you as a brainest and I'll thank you
1 answer:
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Answer:
<h3>1) 5(7
first box: 5 * 7 = 35
35 x^2
second box: 5 * -1 = -5
-5x
third box: 5 * 8 = 40
40
answer: 35 - 5x + 40
<h3>2) 2x(4x^2 + 3x + 6)</h3>
first box: 2x * 4x^2
2 * 4 = 8
x * x^2 = x^3
8x^3
second box: 2x * 3x
2 * 3 = 6
x * x = x^2
6x^2
third box: 2x * 6
2 * 6 = 12
12x
answer: 8x^3 + 6x^2 + 12x
<h3>3) (tp + 5)(4p - 6)</h3>
top left box: tp * 4p
p * p = p^2
4t
top right box: tp * - 6
-6tp
bottom left box: 5 * 4p
5 * 4 = 20
20p
bottom right box: 5 * - 6
5 * -6 = -11
-11
answer: 4tp^2 - 6tp + 20p - 11
<h3>4) (4a - 8)(8a - 1)</h3>
top left box: 4a * 8a
4 * 8 = 32
a * a = a^2
32a^2
top right box: 4a * -1
4 * -1 = -4
-4a
bottom left box: -8 * 8a
-8 * 8 = -64
-64a
bottom right box: -8 * - 1
-8 * - 1 = 8
8
32a^2 - 4a - 64a + 8
<em>combine like terms</em>
32a^2 - 68a + 8 = answer