Answer:
You invested $22,000 in two accounts paying 3% and 5% annual interest, respectively. If the total interest earned for the year was $980, how much was invested at each rate?
Step-by-step explanation:
let x=amt invested at 3% rate of interest.
22000-x=amt invested at 5% rate of interest.
.03x+.05(22000-x)=980
.03x+1100-.05x=980
.02x=120
x=6000
22000-x=16000
amt invested at 3% rate of interest=$6,000
amt invested at 5% rate of interest=$16,000
<h2><em><u>Hope iit help you mark as Brainlist</u></em></h2>
Answer:
-8
Step-by-step explanation:
When you factor, you just find two numbers that add to be the first number (16) and multiply to be the second number (64). 8 and 8 both do this. So when we factor, we also add the variable into each equation because it also has been divided into two equations, and we get: (p + 8)(p +8). Notice that the equations are "+8" and not "-8" because two +8s add to give us a +16 and multiply to give us a +64. After that, we just solve the two equations to find the solutions. Subtract 8 from each equation (we do the opposite operation because 8 is positive) to get -8. Because the answer for each equation is the same our answer is -8.
Good. I hope you get locked, most mainly banned. Nobody needs you, “FrIsK”
Answer:
J. 1
Step-by-step explanation:
Plug the x values into the equation:
f(-1)=3-(-1)^2
f(2)=3-(2)^2
Solve each one, then add.
3-(-1)^2=
=3-1=2
3-(2)^2=
=3-4=-1
Combine the answers together.
2-1=1
The answer is J. 1.
Hope this helps!
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