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kogti [31]
3 years ago
15

Draw a rectangle. Find the area of the rectangle if the length is 30 cm and the width is 72 cm.

Mathematics
2 answers:
Firdavs [7]3 years ago
8 0
2160
That’s what I got
iren2701 [21]3 years ago
7 0

Answer:

the area is 2160

Step-by-step explanation:

length times width equals the area of a rectangle

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Determine area under the standard normal curve given the z score, z less than 1.25
FromTheMoon [43]

Answer:

0.8944

Step-by-step explanation:

Use a calculator or table.

Using a z-score table:

P(z < 1.25) = 0.8944

7 0
3 years ago
X = ??????geometryyyy
Mama L [17]

Answer:

<h3>3.75</h3>

Step-by-step explanation:

Using Secant-Secant theorem we can find the value of x.

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5 × 3 = x × 4

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3 years ago
How to write a story context that would be represented by the ratio 1:4
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5 0
3 years ago
Find the x- and y- intercepts of parabola y=5x^2-16x+10
____ [38]

Y-INTERCEPT

y = 5x^2 - 16x + 10

The y-intercept is where the equation/curve/parabola cosses the y-axis.

The y-axis is where x = 0. (The x-axis is where y = 0)

To find the y-intercept:

\text{y-axis} \rightarrow \text{x = 0} \rightarrow y = 5(0)^2 -16(0) + 10 = 10

The y-intercept must be at (0, 10)

X-INTERCEPT (ROOTS/SOLUTIONS)

y = 5x^2 - 16x + 10\\\text{make it equal 0}\\y = 0\\\therefore 5x^2 - 16x + 10 = 0

We need to use the quadratic formula

The quadratic formula helps us find what values of x make the equation = 0

Quadratic formula: x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-(-16) + \sqrt{(-16)^2-4(5)(10)}}{2(5)}\\\\x = \frac{16 + \sqrt{256-200}}{10}\\x = \frac{16 + \sqrt{56}}{10}\\x = \frac{16 + 2\sqrt{14}}{10}\\x = \frac{8 + \sqrt{14}}{5}\\\\\\x=\frac{-(-16) - \sqrt{(-16)^2-4(5)(10)}}{2(5)}\\\text{doing the same thing...}\\\text{end up with...}\\x = \frac{8 - \sqrt{14}}{5}\\

The x-intercepts are at:

(\frac{8 + \sqrt{14}}{5}, 0)\\(\frac{8 - \sqrt{14}}{5}, 0)

5 0
2 years ago
Solve pls brainliest
Natalija [7]
Answer:

1/4 - 1/8 = 2/8 - 1/8 = 1/8
5 0
2 years ago
Read 2 more answers
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