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2 years ago

What is the missing length?

Mathematics

2 answers:

aliina [53]2 years ago

8 0

Answer:

The missing length is 7

Step-by-step explanation:

Ronch [10]2 years ago

3 0

Answer:

w = 7 inches

Step-by-step explanation:

Area of a parallelogram is b × h and they gave you the height and area, so:

56 = w × 8 (divide by 8 on both sides)

w = 7

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Let V=ℝ2 and let H be the subset of V of all points on the line 4x+3y=12. Is H a subspace of the vector space V?

sergejj [24]

Answer:

No, it isn't.

Step-by-step explanation:

We have $V=IR^{2}$ and let $H$ be the subset of $V$ of all points on the line

$4x+3y=12$

We need to find if $H$ is a subspace of the vector space $V$ .

In $IR^{2}$ all the possibilities for own subspace of the vector space $IR^{2}$ are :

$IR^{2}$ itself.

The vector $0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]$

All lines in $IR^{2}$ that passes through the origin ( $0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]$ )

We know that $H$ is the subset of $IR^{2}$ of all points on the line $4x+3y=12$

If we look at the equation, the point $\left[\begin{array}{c}0&0\end{array}\right]$ doesn't verify it because :

$4x+3y=12\\4(0)+3(0)=12\\0=12$

Which is an absurd. Therefore, $H$ doesn't contain the origin (and $H$ is a line in $IR^{2}$ ). Finally, it can't be a vector space of $V=IR^{2}$

8 0

2 years ago

What is the factored form of the polynomal? x2-12x+27

lianna [129]

Answer:

The answer is $(x-9) (x-3)$ .

Step-by-step explanation:

This is because when you multiply them together you get

$x^{2}$ , $-9x$ , $-3x$ , and $27$

When you add the like terms you get,

$x^{2} - 12x +27$

6 0

2 years ago

Give a 98% confidence interval for one population mean, given asample of 28 data points with sample mean 30.0 and sample standar

klio [65]

We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:

$\begin{gathered} 1-\alpha=0.98 \\ \alpha=0.02 \end{gathered}$

The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:

$CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack$

Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:

$CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack$

Where (from tables):

$Z_{0.99}=2.33$

Finally, the interval at 98% confidence level is:

$CI(\mu)=\lbrack28.94,31.06\rbrack$

4 0

9 months ago

I need help with this

8090 [49]

Answer:

Step-by-step explanation:

9/I0 x 2/2 =9/I0

Or 0.9 in decimals

4 0

2 years ago

Read 2 more answers

Arrange the following in decreasing order. 3.8 m^2 380 cm? 0.038 km2 3,800 mm Which of the following shows the answers in decrea

Snezhnost [94]

Answer:

C. 0.038 km² > 3.8 m² > 380 cm² > 3800 mm²

Step-by-step explanation:

Convert every measurement to the same unit, say, square metres.

(a) 3.8 m²

No conversion necessary

(b) 380 cm²

$\text{Area} = \text{380 cm}^{2} \times \left (\dfrac{\text{1 m}}{\text{100 cm}} \right )^{2} = \textbf{0.038 m}^{2}$

(c) 0.038 km²

$\text{Area} = \text{0.038 km}^{2} \times \left (\dfrac{\text{1000 m}}{\text{1 km}} \right )^{2} = \textbf{38 000 m}^{2}$

(d) 3800 mm²

$\text{Area} = \text{3800 mm}^{2} \times \left (\dfrac{\text{1 m}}{\text{1000 mm}} \right )^{2} = \textbf{0.0038 m}^{2}$

In decreasing order, 0.038 km² > 3.8 m² > 380 cm² > 3800 mm²

6 0

2 years ago