Question

Say you have two parallel current-carrying wires, each carrying a current of 1.0 A and with a distance of 1.0 m between them. What is the magnitude of the force per unit length experienced by each wire

Answer 1

Answer:

$\dfrac{F}{l}=2\times 10^{-7}\ N/m$

Explanation:

Given,

current in the wire I₁ = 1 A

                               I₂ = 1 A

distance between them, r = 1 m

using Force per unit length formula

$\dfrac{F}{l}=\dfrac{\mu_0I_1I_2}{2\pi r}$

$\mu_0 = magnetic\ permeability\ of\ free\ space = 4\pi\times 10^{-7}$

$\dfrac{F}{l}=\dfrac{4\pi \times10^{-7}\times 1\times 1}{2\pi\times 1}$

$\dfrac{F}{l}=2\times 10^{-7}\ N/m$

Hence, the magnitude of force per unit length is equal to $\dfrac{F}{l}=2\times 10^{-7}\ N/m$