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liubo4ka [24]
3 years ago
15

Which changes would result in a decrease in the gravitational force btween two objects? Check all that apply​

Physics
1 answer:
dimulka [17.4K]3 years ago
5 0

Answer:

The answers that apply are;

decreasing the mass of both objects

decreasing the mass of one of the objects

increasing the distance between the objects

The formulae for gravity is; Gravity (g) = GM/R^2;

G is the gravitational constant ( 6.67 × 10^-11)

M is the mass of the planet (in kg)

R is the radius of the planet (in m)

When two objects are pulling on one another then the formula for the gravitational force between them is;

F = (G*m1*m2)/r^2

Therefore, as observed, the gravitational forces are inversely proportional to the distance between the objects and directly proportional mass of the two objects

Explanation:

hope this helps

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Which of the following is a device designed to open an overloaded circuit and prevent overheating?
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Circuit breaker is a device that is designed to open an overloaded circuit and prevent overheating. The correct option in regards to the given question is option "a". The main purpose of the circuit breaker is to disconnect the defective switch from the circuit as soon as any problem arises. This helps in preventing any kind of major accident. Overheating can result in a big accident and the circuit breaker is the device that senses the overheating and disconnects the switch before any major incident. It is an automated system that acts as a protective devise.
4 0
3 years ago
A Pitot-static probe is used to measure the speed of an aircraft flying at 3000 m. If the differential pressure reading is 3300
adell [148]

Answer:

   v = 306.76 Km/h

Explanation:

given,

height of the aircraft = 3000 m

differential pressure reading = 3300 N/m²

density of air = 0.909 Kg/m³

speed of aircraft = ?

Assuming the air flowing above air craft is in-compressible, irrotational and steady so, we can use Bernoulli's equation to solve the problem.

using Bernoulli's equation

          \dfrac{v^2}{2} = \dfrac{\Delta P}{\rho}

where ρ is the density of the air at 3000 m

          v= \sqrt{\dfrac{2 \times \Delta P}{\rho}}

          v= \sqrt{\dfrac{2 \times 3300}{0.909}}

          v = \sqrt{7260.726}

                 v = 85.21 m/s

          v= 85.21 \times \dfrac{3600}{1000}

                 v = 306.76 Km/h

4 0
3 years ago
g A raindrop charged to 10 mC experiences electric field of 10,000 V/m from a tip of a tree branch. What is the electric force a
Andrews [41]

Answer:

The electric force acting on the raindrop is 100 N.

Explanation:

Given;

charge of the raindrop, Q = 10 mC = 0.01 C

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The force acting on the raindrop is given as;

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F = EQ

F = (10,000 N/C) (0.01 C)

F = 100 N

Therefore, the electric force acting on the raindrop is 100 N.

4 0
3 years ago
I don’t know how to explain this or if I am correct:(
Talja [164]

Answer:

c is correct

Explanation:

There are two equal forces on each sides of the rope. The greater opposing sides pull, the greater the magnitude of tension force along the rope.

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3 years ago
Where the hanging wall moves down relative to the footwall, it is an _____________fault
devlian [24]
Tension reverse  is the correct answer.  im not so sure

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