Answer:
1. 12.18g of N2H4.
2. 62.24g of N2H4
3. 87.23g of N2
Explanation:
N2 + 2H2 —> N2H4
Molar Mass of N2 = 2x14 =28g/mol
Molar Mass of N2H4 = (2x14) + (1x4) = 28 + 4 = 32g/mol
Molar Mass of H2 = 2x1 = 2g /mol
Mass conc of H2 from the balanced equation = 2 x 2 = 4g
1. From the balanced equation,
28g of N2 produced 32g N2H4.
Therefore, 10.66 g of N2 will produce = (10.66x32)/28 = 12.18g of N2H4.
2. From the balanced equation,
4g of H2 produced 32g of N2H4.
Therefore, 7.78 g of H2 will produce = (7.78x32)/4 = 62.24g of N2H4
3. From the balanced equation,
28g of N2 produced 32g N2H4.
Therefore, Xg of N2 will produce 99.69 g of N2H4 i.e
Xg of N2 = (28x99.69)/32 = 87.23g
