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tatuchka [14]
3 years ago
10

Molarity formula what is the molarity of a solution in which 3 moles of nacl is dissolved in 1.5 kg of water

Chemistry
1 answer:
Igoryamba3 years ago
7 0
Molarity is..
1.5 kg H₂O = 1.5L H₂O
So...
\frac{moles}{volume} = molarity
\frac{3.0 mol}{1.5L} = molarity
2M = molarity
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Answer:

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what is the molecular formula of the compound?

Empirical formula Molar mass (g/mol) Molecular formula

CHO 116.1

C8H16

Explanation:

Hope this helps

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Which pH value represents a solution with the lowest OHM<br> ion concentration?
Arlecino [84]

pH value 1 represents a solution with the lowest OH⁻ion concentration.

<u>Explanation:</u>

pH is given by the expression as the negative logarithm to the base 10 of the concentration of hydrogen ions.

pH = -log₁₀[H⁺]

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So if the pH is 1, which is most acidic and least basic solution that is lowest OH⁻ ion concentration.

7 0
3 years ago
Oxyacids contains at least one h+ and an oxyanion. the " sulfurous " oxyacid contains the oxyanion ________.
Ulleksa [173]
The correct answer is Oxyanion Nitrite. Oxyanion is referred to as an ion which contains one or more oxygen atoms that are bonded to another chemical element. It has a generic formula of <span>A. </span>x<span>O </span>z− <span>y, wherein A, stands for a chemical element, while O, stands for an Oxygen atom</span>
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Match the following vocabulary words with their definitions.
omeli [17]
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6 0
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Read 2 more answers
A 75.0 g sample of dinitrogen monoxide is confined in a 3.q L vessel. What is the pressure( in atm) at 115 celsius
Nonamiya [84]
Data Given:
                  Pressure  =  P  =  ?

                  Volume  =  V  =  3.0 L

                  Temperature  =  T  =  115 °C + 273  =  388 K

                  Mass  =  m  =  75.0 g

                  M.mass  =  M  =  44 g/mol

Solution:
              Let suppose the Gas is acting Ideally. Then According to Ideal Gas Equation,
                                      P V  =  n R T
Solving for P,
                                      P  =  n R T / V      ------ (1)
Calculating Moles,
                                      n  =  m / M

                                      n  =  75.0 g / 44 g.mol⁻¹

                                      n  =  1.704 mol

Putting Values in Eq. 1,

                    P  =  (1.704 mol × 0.08205 atm.L.mol⁻¹.K⁻¹ × 388 K) ÷ 3.0 L

                    P  =  18.08 atm
7 0
3 years ago
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