Answer:
C. Hb binds O2 more tightly than Mb.
Explanation:
<u>Hb and Mb are both oxygen carrier protiens which contain the heme group. Hb has 4 heme units in 1 moleucle which work via coperative effect. On the other hand, Mb has only one heme unit. </u>
<u>From above theory, statement A and B are correct.</u>
<u>Although the heme group of the Mb is identical to those of Hb, Mb has a higher affinity for carrying oxygen than hemoglobin.</u>
<u>Hence, Statement C is wrong.</u>
Thats why the function of hemoglobin is to transport oxygen and that of myoglobin is to store oxygen.
<u>When a curve is plotted between oxygen accepted and the pressure of the oxygen, Hb shows sigmoidal, whereas Mb shows hyperbolic oxygen saturation curves.</u><u> The statement D is correct.</u>
<u>Bohr effect and various factors decribe the statement : Hb-oxygen binding is dependent on physiological changes in pH, whereas Mb-oxygen binding is not. </u><u>The statement E is also correct.</u>
Answer:
309 liters
Explanation:
A wonderful constant within the gas laws states that 1 mole of any gas occupies 22.4 liters at STP. ANY gas. Make that into a conversion factor you can use at your next social gathering if you want to annoy some friends:
(22.4L/1 mole) for any gas at STP.
Use that factor to find the answer:
(13.8 moles)(22.4L/1 mole) = 309 liters
Answer:
The answer to your question is CuSO₄
Explanation:
To answer your question just remember the following information
- A chemical reaction is divided into sections
reactants and products
reactants on the left side of the reaction
products on the right side of the reaction
- All the symbols have a meaning
(s) means that that compound is in solid phase
(aq) means that that compound is dissolved in solution.
Then, the answer is CuSO₄
<span>Answer: FALSE:
Explanation:
A reaction requires 22.4l of at STP. You have 32.0l of gas at 398k and 105.6 kpa.
1) STP stands for standard temperature and pressure.
2) Standard temperature is 0°C or 273.15 K
3) Standard pressure is 1 atm or 1013.25 kPa
4) use the ideal gas equation for both contidions
pV = n RT
=> n * R = pV /T
at STP n * R = 1031.25 kPa * 22.4 liter / 273.15 K = 84.5
at T = 398 K, p = 105.6 kPa, and V = 3.2.0 liter:
n * R = 105.6 kPa * 32.0 liter / 398 K = 8.49
Since R is a constant (the Universal Gases Constant), it is evident that the number of moles in the 32.0 liter of gas, at T = 398 K and P = 105.6 kPa is less than the number of moles of the 22.4 liter gas at STP.
There is not enough gas to carry out the reaction.
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