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malfutka [58]
3 years ago
15

In the following unbalanced chemical reaction, what belongs in the blank? C8H18 + O2à CO2 + H2O + _________ A. CO B. CO3 C. ener

gy D. nothing
Chemistry
2 answers:
kakasveta [241]3 years ago
7 0

Answer:

C. energy

2C8H18 + 25O2 \rightarrow 16CO2 + 18H2O + energy

Explanation:

The balanced reaction is:

2C8H18 + 25O2 \rightarrow 16CO2 + 18H2O

This is essentially a combustion reaction in which a hydrocarbon such as octane in this case, reacts with oxygen to form carbon dioxide and water. Combustion reactions are exothermic  which implies that energy is released as the reaction progresses. Thus, the given reaction can be represented by adding the term 'energy' to the product side of the reaction:

2C8H18 + 25O2 \rightarrow 16CO2 + 18H2O + energy

Sergeu [11.5K]3 years ago
3 0
Your answer is C energy hope it helps:)
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In a particular breed of cattle, a black coat is dominant over a red coat. If a cow with a red coat is crossed with a black bull
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3 years ago
Molarity of 0.50 mol sugar in 270 mL of solution.
EastWind [94]
<h3>Answer:</h3>

1.85 M

<h3>Explanation:</h3>

<u>We are given;</u>

  • Number of moles as 0.50 mol
  • Volume of the solution is 270 ml

But, 1000 mL = 1 L

  • Thus, volume of the solution is 0.27 L

We are required to calculate the molarity of the solution;

  • Molarity refers to the concentration of a solution in moles per liter.
  • It is calculated by dividing number of moles with the volume.

Molarity = Moles ÷ Volume

In this case;

Molarity = 0.50 moles ÷ 0.27 L

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Therefore, molarity of the solution is 1.85 M

5 0
3 years ago
Determine the ph of a 0.18 m h2co3 solution. carbonic acid is a diprotic acid whose ka1 = 4.3 × 10-7 and ka2 = 5.6 × 10-11. dete
oee [108]
Answer is: ph value is 3.56.
Chemical reaction 1: H₂CO₃(aq) ⇄ HCO₃⁻(aq) + H⁺(aq); Ka₁ = 4,3·10⁻⁷.
Chemical reaction 2: HCO₃⁻(aq) ⇄ CO₃²⁻(aq) + H⁺(aq); Ka₂ = 5,6·10⁻¹¹.
c(H₂CO₃) = 0,18 M.
[HCO₃⁻] = [H⁺<span>] = x.
</span>[H₂CO₃] = 0,18 M - x.
Ka₁ = [HCO₃⁻] · [H⁺] / [H₂CO₃].
4,3·10⁻⁷ = x² / (0,18 M -x).
Solve quadratic equation: x = [H⁺] =0,000293 M.
pH = -log[H⁺] = -log(0,000293 M).
pH = 3,56; second Ka do not contributes pH value a lot.


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