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galben [10]
3 years ago
15

P + 02 → _P205 What is the answer

Chemistry
1 answer:
Artemon [7]3 years ago
3 0

Answer:

Explanation:

the given equation is not balance

the balance equation can be written as

4P+5O2...........2P2O5

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For each reaction, write the chemical formulae of the oxidized reactants in the space provided. Write the chemical formulae of t
liberstina [14]

Explanation:

First Reaction;

Ca + ZnCl2 --> CaCl2 + Zn

Oxidized Reactant: Ca. There is increase in oxidation number from 0 to +2

Reduced Reactant: Zn. There is decrease in  oxidation number form +2 to 0

Second Reaction:

FeI2 + Mg --> Fe + MgI2

Oxidized Reactant: Mg. There is increase in oxidation number from 0 to +2

Reduced Reactant: Fe. There is decrease in  oxidation number form +2 to 0

Third Reaction;

Mg + 2AgNO3 --> Mg(NO3)2 + Ag

Oxidized Reactant: Mg. There is increase in oxidation number from 0 to +2

Reduced Reactant: Ag. There is decrease in  oxidation number form +1 to 0

5 0
3 years ago
What produced the sulfuric acid that helped form the Lechugilla caves
Mila [183]
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7 0
3 years ago
Determine the number of moles of aluminum in 2.154 x 10-1 kg of Al. Group of answer choices 5816 mol 7.984 mol 6.02 X 1023 mol 4
Jlenok [28]

Answer:

Avogadro's number is 1 mol  = 6.02 * 10^23 elements

It means that 1 mol of atoms is 6.02 * 10^23 atoms

1 mol of atoms = 6.02 * 10^23 atoms

From there, if you divide both sides by 1 mol of atoms, you get

1 = 6.02 * 10^23 atoms / 1 mol of atoms.

That means, that to pass from a number of moles of atoms to number of atoms you have to multipby by the conversion factor

         6.02*10^23  atoms Al/ 1 mol Al

That is the second option of the list.

Explanation:

8 0
3 years ago
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Llana [10]

Answer:

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A mnemonic technique that could be used is that the process that starts with a vowel (Oxidation) takes place at the place that also starts with a vowel (Anode).

7 0
3 years ago
Which isotope of nirtogen is more abundent?
Jobisdone [24]
<span>Nitrogen-14 should be the correct response.</span>
6 0
3 years ago
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