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yawa3891 [41]
2 years ago
10

For each reaction, write the chemical formulae of the oxidized reactants in the space provided. Write the chemical formulae of t

he reduced reactants in the space provided.
Chemistry
1 answer:
liberstina [14]2 years ago
5 0

Explanation:

First Reaction;

Ca + ZnCl2 --> CaCl2 + Zn

Oxidized Reactant: Ca. There is increase in oxidation number from 0 to +2

Reduced Reactant: Zn. There is decrease in  oxidation number form +2 to 0

Second Reaction:

FeI2 + Mg --> Fe + MgI2

Oxidized Reactant: Mg. There is increase in oxidation number from 0 to +2

Reduced Reactant: Fe. There is decrease in  oxidation number form +2 to 0

Third Reaction;

Mg + 2AgNO3 --> Mg(NO3)2 + Ag

Oxidized Reactant: Mg. There is increase in oxidation number from 0 to +2

Reduced Reactant: Ag. There is decrease in  oxidation number form +1 to 0

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Use the molar solubility 3.27×10−11m in pure water to calculate ksp for nis.
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Answer:

Ksp = 1.07x10⁻²¹

Explanation:

Molar solubility is defined as moles of solute can be dissolved in 1L.

Ksp for NiS is defined as:

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Replacing:

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<em>Ksp = 1.07x10⁻²¹</em>

<em></em>

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After a reaction, a new compound contains 0.73 g Mg and 0.28 g N. What is the empirical formula of this compound?
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Answer:

Mg₃N₂

Explanation:

The empirical formula of a chemical compound is defined as the simplest positive integer ratio of atoms present in a compound. Using molecular mass of Mg (24,305g/mol) and mass of nitrogen (14,006g/mol), moles of each element are:

0,73g × (1mol / 24,305g) = 0,03 moles of Mg

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Dividing each value in 0,01 to obtain natural numbers:

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I hope it helps!

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