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yawa3891 [41]
3 years ago
10

For each reaction, write the chemical formulae of the oxidized reactants in the space provided. Write the chemical formulae of t

he reduced reactants in the space provided.
Chemistry
1 answer:
liberstina [14]3 years ago
5 0

Explanation:

First Reaction;

Ca + ZnCl2 --> CaCl2 + Zn

Oxidized Reactant: Ca. There is increase in oxidation number from 0 to +2

Reduced Reactant: Zn. There is decrease in  oxidation number form +2 to 0

Second Reaction:

FeI2 + Mg --> Fe + MgI2

Oxidized Reactant: Mg. There is increase in oxidation number from 0 to +2

Reduced Reactant: Fe. There is decrease in  oxidation number form +2 to 0

Third Reaction;

Mg + 2AgNO3 --> Mg(NO3)2 + Ag

Oxidized Reactant: Mg. There is increase in oxidation number from 0 to +2

Reduced Reactant: Ag. There is decrease in  oxidation number form +1 to 0

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Cerrena [4.2K]

Answer:

2.67 mL

Explanation:

The following data were obtained from the question:

Mass of tetracycline = 2 mg

Density of tetracycline = 0.75 mg/mL

Volume of tetracycline =?

We can obtain the volume of the tetracycline that should be given to the patient by applying the following equation:

Density = mass /volume

0.75 = 2 / volume

Cross multiply

0.75 × Volume = 2

Divide both side by 0.75

Volume = 2/0.75

Volume = 2.67 mL

Therefore, the volume of the tetracycline that should be given to the patient is 2.67 mL

6 0
3 years ago
Will a horse galloping in a field produce and average velocity of zero
motikmotik

Answer:

No

Explanation:

Depending on the mass of the horse and the speed, velocity will change.

5 0
3 years ago
(WILL MARK BRAINLIEST)<br> PLZ HELP ASAP
ArbitrLikvidat [17]

Answer:

a) 2NaOH(aq) + CuSO4(aq) -------------> Cu(OH)2(s) + Na2SO4(aq)

b) Ca(OH)2(aq) + CO2(g) --------------> CaCO3 + H2O (this is already balanced)

c) Pb(NO3)2 + H2SO4 --------> PbSO4 + 2HNO3.

d) 2KNO3 ------> 2KNO2 + O2

e) H2SO4 + 2(NaOH) -----> Na2SO4 + 2(H2O)

f) Ca(NO3)2(aq) + (NH4)2CO3(aq) ----------------> CaCO3(s) + 2NH4NO3(aq)

3 0
3 years ago
Read 2 more answers
A cylindrical glass tube of length 27.4cm and radius 4 cm is filled with gas. The empty tube has a mass of 254.3 g. The tube fil
Temka [501]

Density of the gas is 3.05 × 10⁻³ g / cm³.

<u>Explanation:</u>

Volume of the cylinder = π r² h

where r is the radius and h is the height of the height or the length of the glass tube.

Here r = 4 cm and h = 27.4 cm

Volume of the cylinder = 3.14 × 4 × 4 × 27.4 = 1376.6 cm³

We have to find the mass of the gas by subtracting the mass of the tube filled with the substance from the mass of the empty tube.

Mass of the substance = 258.5 - 254.3 = 4.2 g

We have to find the density using the formula as,

$ Density = \frac{mass}{volume}

Plugin the values as,

$ Density = \frac{4.2}{1376.6}

              = 3.05 × 10⁻³ g / cm³

So the Density of the gas is 3.05 × 10⁻³ g / cm³.

3 0
3 years ago
Convert 3841 cL to L. SHOW WORK PLS
barxatty [35]

Answer:

1 cl = 1 * 10-5 m³

1 L = 1 * 10-3 m³

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1 m³ = (1/0.001) L

1 m³ = 1000 L

1 cl = 1 * 10-5 * 1000 L

1 cl = 0.01 L

4 0
2 years ago
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