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vladimir1956 [14]
3 years ago
11

What is a cut circuit

Chemistry
1 answer:
Luden [163]3 years ago
6 0

Answer:

a CUT stands for Circuit Under Test.

Explanation:

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If 90.0 grams of ethane reacted with excess chlorine,how many grams of dicarbon hexachloride would form
tigry1 [53]

Answer:

709 g  

Step-by-step explanation:

a) Balanced equation

Normally, we would need a balanced chemical equation.

However, we can get by with a partial equation, as log as carbon atoms are balanced.

We know we will need an equation with masses and molar masses, so let’s <em>gather all the information</em> in one place.  

M_r:    30.07          236.74

           C₂H₆ + … ⟶ C₂Cl₆ + …  

m/g:    90.0

(i) Calculate the moles of C₂H₆

n = 90.0 g C₂H₆  × (1 mol C₂H₆ /30.07 g C₂H₆)

  = 2.993 mol C₂H₆

(ii) Calculate the moles of C₂Cl₆

The molar ratio is (1 mol C₂Cl₆/1 mol C₂H₆)

n = 2.993 mol C₂H₆ × (1 mol C₂Cl₆/1 mol C₂H₆)

  = 2.993 mol C₂Cl₆

(iii) Calculate the mass of C₂Cl₆

m = 2.993 mol C₂Cl₆ × (236.74 g C₂Cl₆/1 mol C₂Cl₆)

m = 709 g C₂Cl₆

The reaction produces 709 g C₂Cl₆.

6 0
3 years ago
) Consider the starting materials and reagents. What do you expect to happen at the beginning of this reaction (Boxes 1-3 on the
tekilochka [14]

Answer:

Check the explanation

Explanation:

functional group found in the major organic product = alpha -beta unsaturated ketone

Reaction used to form this functional group = Michael condensation reaction

Also other reactions are - Aldol condensation , Robinson annulation reaction.

Kindly check the attached image below to see the step by step solution to the question above.

3 0
3 years ago
Which model was proposed as a result of Rutherford's scattering experiment where positive particles did not pass straight throug
dimulka [17.4K]

Answer:

the nuclear model of the atom

6 0
3 years ago
The compound tyrosine contains 59.66% C, 6.12% H, 7.73% N, and 26.49% O by mass. What is the empirical formula of tyrosine?
ycow [4]

Answer: C9H11O3N

Explanation:

The percentage by mass of each element is divided by its relative atomic mass. The lowest ratio is now observed. Each ratio is now divided by this lowest ratio and approximated to whole numbers. All these are shown in detail in the image attached.

6 0
4 years ago
A 4.215 g sample of a compound containing only carbon, hydrogen, and oxygen is burned in an excess of oxygen gas, producing 9.58
Scilla [17]

Answer:

\% O=27.6\%

Explanation:

Hello,

In this case, for the sample of the given compound, we can compute the moles of each atom (carbon, hydrogen and oxygen) that is present in the sample as shown below:

- Moles of carbon are contained in the 9.582 grams of carbon dioxide:

n_C=9.582gCO_2*\frac{1molCO_2}{44gCO_2}*\frac{1molC}{1molCO_2}  =0.218molC

- Moles of hydrogen are contained in the 3.922 grams of water:

n_H=3.922gH_2O*\frac{1molH_2O}{18gH_2O} *\frac{2molH}{1molH_2O} =0.436molH

- Mass of oxygen is computed by subtracting both the mass of carbon and hydrogen in carbon dioxide and water respectively from the initial sample:

m_O=4.215g-0.218molC*\frac{12gC}{1molC} -0.436molH*\frac{1gH}{1molH} =1.163gO

Finally, we compute the percent by mass of oxygen:

\% O=\frac{1.163g}{4.215g}*100\% \\\\\% O=27.6\%

Regards.

5 0
4 years ago
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