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2 years ago

What happens at the anode in an electrolytic cell?

Chemistry

1 answer:

Llana [10]2 years ago

7 0

Answer:

D. Oxidation

Explanation:

In an electrolytic cell, oxidation (the loss of electrons) takes place at the anode. At the cathode reduction takes place.

A mnemonic technique that could be used is that the process that starts with a vowel (Oxidation) takes place at the place that also starts with a vowel (Anode).

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Identify the balanced equation for the following reaction: SO2(g) + O2(g) → SO3(g)

sergiy2304 [10]

Answer: The balanced equation for the given reaction is

$2SO_{2}(g) + O_{2}(g) \rightarrow 2SO_{3}(g)$ .

Explanation:

A chemical equation which contains same number of atoms on both reactant and product side.

For example, $SO_{2}(g) + O_{2}(g) \rightarrow SO_{3}(g)$

Here, number of atoms on reactant side are as follows.

S = 1

O = 4

Number of atoms on product side are as follows.

S = 1

O = 3

To balance this equation, multiply $SO_{2}$ by 2 on reactant side and multiply $SO_{3}$ by 2. Hence, the equation will be re-written as follows.

$2SO_{2}(g) + O_{2}(g) \rightarrow 2SO_{3}(g)$

Here, number of atoms on reactant side are as follows.

S = 2

O = 6

Number of atoms on product side are as follows.

S = 2

O = 6

Now, there are same number of atoms on both reactant and product side. So, this equation is balanced.

Thus, we can conclude that the balanced equation for the given reaction is $2SO_{2}(g) + O_{2}(g) \rightarrow 2SO_{3}(g)$ .

3 0

2 years ago

Which of the following sequences of elements would all have four valence electrons?

timama [110]

Answer:b

Explanation:

8 0

2 years ago

In metallic bonds, the mobile electrons surrounding the positive ions are called a(n)?

Anastaziya [24]

Answer: In metallic bonds, the mobile electrons surrounding the positive ions are called dipole.

6 0

3 years ago

If the temperature of the water were 0°C and the pressure was above 760 mm Hg, what phase would the water be in?

viva [34]

I would say the answer is gas.

4 0

2 years ago

If 15.0 mL of phosphoric acid completely neutralizes 38.5 mL of 0.150 mol/L calcium hydroxide, what is the concentration of the

Sedbober [7]

Answer:

Let me give it a try.

H3PO4 + Ca(OH)2 = Ca3(PO4)2 + H2O

Balancing this reaction

2H3PO4 + 3Ca(OH)2 == Ca3(PO4)2 + 6H2O.

Moles= Molarity x Volume

Volume = 38.5ml = 0.0385L

Moles of Ca hydroxide = 0.150m/L x 0.0385L

(Notice the units canceling out...leaving moles).

=0.005775moles of Ca(OH)2.

From balanced reaction...

3moles of Ca(OH)2 completely reacts with 2moles of H3PO4

0.005775moles of Ca(OH)2 would completely react with....

= 0.005775 x 2/(3)

=0.00385moles of H3PO4.

Now we're looking for its Concentration in Mol/L

Molarity=Moles of solute/Volume of solution(in L)

Volume of solution assuming no other additions to the reaction = 15ml + 38.5ml =53.5ml =0.0535L

Molarity = 0.00385/0.0535

=0.072Mol/L.

If this is wrong

then Simply Try The formula for Mixing of solutions

C1V1 = C2V2

0.15 x 38.5 = C2 x (15+38.5)

C2 = 0.11M/L.

7 0

3 years ago