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3 years ago

What produced the sulfuric acid that helped form the Lechugilla caves

1 answer:

7 0

The answer you need is B. Pollution. Have in mind that Caves contain carvings and depictions that are formed from acids running through the limestones of the cave. The sulfuric acid that helped form the Lechugilla caves come from pollution.I hope this info can help you

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Alka-Seltzer is a solid mixture of two substances, sodium bicarbonate (NaHCO3) and citric acid (H3C6H5O7). The substances react

laiz [17]

1) List the reactants: sodium bicarbonate (NaHCO₃) and citric acid (H₃C₆H₅O₇).

Reactants undergo change during a chemical reaction.

2) List the products: water (H₂O), carbon dioxide (CO₂) and sodium citrate (Na₃C₆H₅O₇).

Products are the substances formed from chemical reactions.

3) The balanced chemical equation:

3NaHCO₃ + H₃C₆H₅O₇ → 3H₂O + 3CO₂ + Na₃C₆H₅O₇.

6 0

3 years ago

Balance the following equation: __Ch4+__O2→__CO2+__H2O

konstantin123 [22]

Answer:

1,2,1,2

Explanation:

You would need only one of the CH4 but 2 of the O2 then 1 CO2 and 2 H2O on each side of the equation you now have 1 carbon, 4 hydrogen, and 4 oxygen.

3 0

2 years ago

Can anyone do this question.i really need a answer

PilotLPTM [1.2K]

Answer:

17.4

Explanation:

kasi 15.2

16.2

=17.4 thanks me later pa brainliest din

7 0

3 years ago

What is the cost of carbon in gram

Morgarella [4.7K]

Carbon is 12 grams per mole

6 0

3 years ago

Calculate the energy of one photon of yellow light that has a wavelength of 5.89x10^-7m.

Viktor [21]

Answer:

E = energy = ? ,

λ = Wavelength = 5.89 × 10^-7 m —> = 589 ×10 ^-9 m ,

h =Planck constant = 6.63 × 10^-34 J.s ,

f = frequency of photo/ electromagnetic radiation = c/λ ,

c = Speed of light in a vacuum = 3 × 10^8 m/s

___o___o____

$E = hf \\ \\ E = h \frac{c}{λ} \\ \\ E = 6.63 \times {10}^{ - 34} \frac{3 \times {10}^{8} }{5.89 \times {10}^{ - 7} } \\ \\E = \frac{6.63 \times {10}^{ - 34} \times 3 \times {10}^{8} }{5.89 \times {10}^{ - 7} } \\ \\ E = \frac{663 \times {10}^{ - 36} \times 3 \times {10}^{8} }{589 \times {10}^{ - 9} } \\ \\ E = \frac{1989 \times {10}^{ - 28} }{589 \times {10}^{ - 9} } \\ \\ E = 3.37691 \times {10}^{ - 19} J$

I hope I helped you^_^

8 0

2 years ago