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3 years ago

Study the function below and then answer the questions that follow.

Mathematics

2 answers:

Licemer1 [7]3 years ago

4 0

Answer:

Domain: all real values of x except -2

Range: y > -4

Step-by-step explanation:

Domain: union of all intervals of x

x < -2 U -2 < x < 0 U x》0

This includes all real values of x except x = -2

When x < -2

-x - 2 > 0

When -2 < x < 0

-4 < -x² < 0

When x》0

x》0

Range is the union of all these outputs

y > 0 U -4 < y < 0 U y》0

y > -4

NeX [460]3 years ago

3 0

Answers and Step-by-step explanations:

Notice that -2 is not included in the inequality, but any other number is. That means that the domain is all real numbers except x = -2.

For the range, I recommend you draw a graph (see the attachment).

As can be seen, the range will be y > -4.

Hope this helps!

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Cuanto es menos 7 mas 2

irina [24]

Answer:

the answer is -5. you could really just use a calculator this is pretty basic math.

Step-by-step explanation:

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3 years ago

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Lemur [1.5K]

Answer:

Powers of the variable descending left to right
right side of the equal sign is 0

Step-by-step explanation:

For some constants a, b, and c, the standard form* is ...

ax^2 + bx + c = 0

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It is nice if the leading coefficient (a) is positive, but that is not required.

The main ideas are that ...

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3 years ago

Number 1. The science club went on a two-day field trip. The first aid the members paid $60 for transportation plus $15 per tick

tekilochka [14]

If x is the number of students on the field trip:
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4 years ago

Which of the following represents 5x 4/9 in radical formj

solong [7]

$\bf a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
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-------------------------------\\\\
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4 years ago

50+51+52+...+101=...<br>Can you help me? I do not understand

Dmitriy789 [7]

Suppose

$S=50+51+52+\cdots+100+101$

At the same time, we can write

$S^*=101+100+99+\cdots+51+50$

Note that $S=S^*$ (just reverse the sum). Let's pair the first terms of $S$ and $S^*$ , and the second, and the third, and so on:

$S+S^*=(50+101)+(51+100)+(52+99)+\cdots+(100+51)+(101+50)$

Now, each grouped term in the sum on the right side adds to 151. There are 52 grouped terms on that same side (because there are 50 numbers in the range of integers 51-100, plus 50 and 101), which menas

$S+S^*=52\cdot151$

But $S=S^*$ , as we pointed out, so

$2S=52\cdot151\implies S=\dfrac{52\cdot151}2=3926$

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3 years ago