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goblinko [34]
3 years ago
10

1 lb equals how many grams

Physics
2 answers:
shusha [124]3 years ago
8 0

Answer:

1 lb. is 453.592 grams

Explanation:

1lb is 453.592 grams

Amiraneli [1.4K]3 years ago
8 0
453.592 grams hope this helps!
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3 holits = 5 gorfs<br> 7 gorfs = 2 queets<br> How many queets are there in 43 holits?
Paha777 [63]

Explanation:

43 holits × (5 gorfs / 3 holits) × (2 queets / 7 gorfs) ≈ 20.5 queets

3 0
3 years ago
If the voltage in a circuit is 24 V and the current is 2 A, what is the total power in the circuit?
Drupady [299]
Maybe you can divide the volts its twelve if you do that but itll show you how much to double it by

5 0
4 years ago
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In a television set the power needed to operate the picture tube comes from the secondary of a transformer. The primary of the t
Natasha2012 [34]

Answer:

c)  N_s / N_p = 115.15

Explanation:

Let's look for the voltage in the secondary, they do not indicate the power dissipated

          P = V_s i

          V_s = P / i

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          V_s = 13.818 10³ V

the relationship between the primary and secondary of a transformer is

           \frac{V_p}{N_p} = \frac{V_s}{N_s}

           \frac{N_s}{N_p} = \frac{V_s}{V_p}

           Ns / Np = 13,818 10³ /120

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4 0
3 years ago
What was john philip career​
goldfiish [28.3K]

Answer:

John Philip Sousa gained great proficiency on the violin,  age of 13 he was almost persuaded to join a circus band,his father intervened and enlisted him as an apprentice musician in the Marine Band, Louis, he received a telegram offering him the leadership of the Marine Band in Washington

Explanation:

3 0
3 years ago
While buying a hot plate you notice the resistance of the hot plate is 25.0 . when connected to a 120. v source, how much curren
klemol [59]
The basic relationship between voltage, resistance and current of an electrical device is given by Ohm's law:
V=IR
where
V is the voltage
I is the current
R is the resistance

The hot plate in our problem is connected to a source of V=120 V and it has a resistance of R=25.0 \Omega, therefore we can rearrange the previous equation to calculate the current through the device:
I= \frac{V}{R}= \frac{120 V}{25.0 \Omega}=4.8 A
4 0
4 years ago
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