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2 years ago

the velocity of a curling stone is due east. what will be the direction of the momentum of the curling stone as it moves?

Physics

2 answers:

kirill [66]2 years ago

8 0

East.
momentum = mass x velocity
the direction of the momentum is the same as that of velocity.

7nadin3 [17]2 years ago

7 0

Answer: to east.

Explanation: Momentum is the "amount of movement" and can be written as:

P = m*v

where P is momentum, m is the mass of an object moving and v is the velocity of the object.

As you may know, the velocity is a vector and the mass is a scalar, so the momentum must be also a vector, that has the same direction that the vector of velocity, so if the velocity of the rock points to the east, also does the momentum.

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A submarine sends a signal and receives an echo after 5 seconds. Calculate the speed of sound if distance of object from submari

Reil [10]

$speed = distance \div time$
Since the sound travels from the submarine to the object AND back, it actually travelled 3625x2=7250m.

$7250 \div 5 = 1450$
Speed of sound: 1450m/s

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3 years ago

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A ductile metal wire has resistance R. What will be the resistance of this wire in terms of R if it is stretched to three times

Ira Lisetskai [31]

Answer:

Explanation:

We know that the resistance is $R=\rho *\frac{L}{A}$ .

If we stretch the wire to a new length L2 = 3L, the cross-sectional area will also change. If the cross-sectional area doesn't change throughout the wire, we can say that:

Volume = L*A = 3L * A2 being A2 the new area after stretching the wire.

Since the volume remains the same we conclude that A2 = A/3

With this information, we calculate the new resistance:

$R2=\rho *\frac{L2}{A2}=\rho *\frac{3*L}{A/3}=\rho * 9 * \frac{L}{A}$

Since $R=\rho *\frac{L}{A}$ , and by simple inspection of the previous equation, we get:

R2 = 9*R

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2 years ago

You push the ball with aforce of 22.8N which induces a -2.3N frictional force. What is the net force while you push?

inna [77]

The net force is 22.8-2.3 or 20.5 N

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2 years ago

Particles 1 and 2 of charge q1 = q2 = +3.20 × 10−19 C are on a y axis at distance d = 17.0 cm from the origin. Particle 3 of cha

mel-nik [20]

Answer:

(a) 0.17 m

(b) 5.003 m

(d) 7.37 × $10^{-29}$ N

Explanation:

(a) The minimum value of $x$ will occur when q3 = 0 m or at origin and q1, q2 are at 0.17 m so the distance between q3 and q1, q2 is 0.17 m, therefore the minimum value of x= 0.17 m.

(b) The maximum value of x will occur when q3 = 5 m because it is said in the question that 5 is the maximum distance travelled by q3. To find the hypotenuse i.e. the distance between q3 and q1,q2, we use Pythagoras theorem.

$h^{2} = b^{2} + p^{2}$