Answer:
the smallest angle from the antennas is <em>47.3°</em>
Explanation:
We first need to write the expression for the relation between the wavelength (λ) and the frequency (f) of the wave, and then solve for the wavelength.
Therefore, the relation is:
λ = c /f
where
- c is the speed of light constant
- λ is the wavelength
- f is the frequency
Thus,
λ = (3 × 10⁸ m/s) / (3.4 MHz)
= (3 × 10⁸ m/s) / (3.4 MHz)(10⁶ Hz/1 MHz)
= 88.235 m
Therefore, the smallest angle measured (from the north of east) from the antennas for the constructive interference of the two-radio wave can be calculated as
θ = sin⁻¹(λ / d)
where
- d is the distance between the two radio antennas
Thus,
θ = sin⁻¹(88.235 / 120)
<em>θ = 47.3 °</em>
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Therefore, the smallest angle from the antennas, measured north of east, at which constructive interference of two radio waves occurs is <em>47.3 °</em>.
Mass=600kg
Velocity =15m/s
Momentum(p)=?
Now,
P=mass x velocity
=600x15
=9000kgm/s
Answer:c>a>b
Explanation:
Given
All the engine extracts same amount of heat(Q) from High-temperature reservoir
For a) 400 and 500 K
For b)500 K and 600K
For c) 400 K and 600 K
So c will give the highest amount of work
c>a>b
What does this supposed to mean?
