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3 years ago

Occurs naturally between organisms living in an environment with limited resources.

Biology

2 answers:

Yanka [14]3 years ago

8 0

I think the answer is A. Competition. :)

inessss [21]3 years ago

4 0

A.competition would be the correct answer I believe

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dybincka [34]

Answer:

Plants and trees are the primary sources of food for a food chain or a food web. If the population of the primary producers reduces than it affects the whole food web. If the deciduous trees are destroyed due to a fire, there will be less food available for the primary predators. As a result, competition will begin between them and their population will decline. Due to this, the population of other organisms which fed on the primary consumers will also decline.

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4 years ago

The liver of a dog has been found to have higher than normal cell death because the DNA is damaged. What part of the cell failed

NikAS [45]

The answer is Nuclear envelope.

Basically, the Nuclear envelope is an outer shell that protects the cell (which includes the dna) from any harmful things.

6 0

3 years ago

Read 2 more answers

Why is reducing caloric intake insufficient for a person to loose weight in a healthy way?

garri49 [273]

Because there are several factors that determine weight loss or gain and reducing calorific intake is just one of them (for reducing weight loss). Other factors that should be considered is exercise. Doing regular exercise ensures that the metabolic rate of the body is increased so much of the calories are burned even after intake. Having a lower metabolic rate can result to increased weight gain even with low calorie intake.

3 0

3 years ago

1. cells are the basic units of________and_______in all living things.

Ludmilka [50]

Answer:

1. Life, exist 2. pre-existing cells.

Explanation:

3 0

3 years ago

22. A plant geneticist is investigating the inheritance of genes for bitter taste (Su) and explosive rind (e) in watermelon (Cit

mylen [45]

Answer:

See the answer below

Explanation:

Using the formula for calculating Chi square ( $X^2$ ):

$X^2$ = $\frac{(O - E)^2}{E}$ where O = observed frequency and E = expected frequency.

The observed frequencies for the four phenotypes are 88, 62, 62, and 81 respectively.

For the expected frequency, the phenotypes are supposed to assort in 9:3:3:1 according to Mendel ratio.

Hence, expected frequencies are calculated as:

phenotype (1) = 9/16 x 293 = 164.81

phenotype (2) = 3/16 x 293 = 54.94

phenotype (3) = 3/16 x 293 = 54.94

phenotype (4) = 1/16 x 293 = 18.31

The $X^2$ is calculated thus:

Phenotype O E $X^2$

1 88 164.81 $\frac{(88 - 164.81)^2}{164.81}$ = 35.80

2 62 54.94 $\frac{(62 - 54.94)^2}{54.94}$ = 0.91

3 62 54.94 $\frac{(62 - 54.94)^2}{54.94}$ = 0.91

4 81 18.31 $\frac{(81 - 18.31)^2}{18.31}$ = 214.64

Total $X^2$ = 35.80 + 0.91 + 0.91 + 214.64 = 252.26

To the nearest tenth = 252

Degree of freedom = n - 1 = 4- 1 = 3

$X^2$ tabulated = 7.815

<em>The calculated </em> $X^2$ <em> exceeds the critical value, hence, the null hypothesis is rejected. The two genes did not assort independently. </em>

4 0

3 years ago