I need help with this please: How much energy would be required to vaporize 45.0 grams of water?

Gastric acid plays a key role in the digestion of proteins by activating digestive enzymes and often has a pH value in the range

faust18 [17]

If the pH of the acid at a given time is found to be 1.25, then the molarity of the gastric acid juice is 0.056M.

pH is define as the negative logarithm of the concentration of H⁺ ions present in any solution and it will be represented as:

pH = -log[H⁺]

Concentration will be present in the form of molarity and pH value for gastric acid is given 1.25 means it is strong acid as it completely dissociates into their ions.

Required equation for calculation will be:

[H⁺] = $10^{-pH}$

[H⁺] = $10^{-1.25}$

[H⁺] = 0.056 M

Hence molarity of the gastric acid juice is 0.056M.

To know more about pH & molarity, visit the below link:

brainly.com/question/27298208

6 0

3 years ago

Is putting food coloring in water a chemical change?

nata0808 [166]

Yes, Yes it is. Food coloring has chemicals in it

5 0

3 years ago

g Suppose a 49. L reaction vessel is filled with 1.5 mol of NO. What can you say about the composition of the mixture in the ves

irakobra [83]

The question is incomplete, the complete question is:

At a certain temperature, the equilibrium constant $K_{eq}$ for the following reaction is 0.74:

$NO_3(g)+NO(g)\rightleftharpoons 2NO_2(g)$

Suppose a 49.0 L reaction vessel is filled with 1.5 mol of $NO_3$ and 1.5 mol of NO. What can you say about the composition of the mixture in the vessel at equilibrium?

A. There will be very little $NO_3$ and NO.

B. There will be very little $NO_2$

C. Neither of the above is true.

<u>Answer:</u> The correct option is B. there will be very little $NO_2$

<u>Explanation:</u>

We are given:

Initial moles of $NO_3$ = 1.5 moles

Initial moles of NO = 1.5 moles

Volume of vessel = 49 L

As, moles of reactants and moles of products are equal, the volume term will not appear in the equilibrium constant expression.

Equilibrium constant for the reaction = 0.74

For the given chemical equation:

$NO_3(g)+NO(g)\rightleftharpoons 2NO_2(g)$

Initial: 1.5 1.5 -

At eqllm: 1.5-x 1.5-x 2x

The expression of equilibrium constant for the above reaction:

$K_{eq}=\frac{[NO_2]^2}{[NO_3]\times [NO]}$

Putting values in above equation, we get:

$0.74=\frac{(2x)^2}{(1.5-x)(1.5-x)}\\\\x=-1.13, 0.451$

Neglecting the negative value of equilibrium constant because concentration cannot be negative

Equilibrium concentration of $NO_3$ = (1.5 - x) = (1.5 - 0.451) = 1.049 moles

Equilibrium concentration of NO = (1.5 - x) = (1.5 - 0.451) = 1.049 moles

Equilibrium concentration of $NO_2$ = 2x = $(2\times 0.451)=0.902mol$

There are 3 possibilities:

If $K_{eq}$ , the reaction is reactant favored
If $K_{eq}>1$ , the reaction is product favored.
If $K_{eq}=1$ , the reaction is in equilibrium.

Here, the value of $K_{eq}=0.74$ , which is less than 1, therefore the reaction is reactant favored and we can say that there will be very little $NO_2$ .

Hence, the correct option is B. there will be very little $NO_2$

7 0

3 years ago

High concentrations of ammonia (NH3), nitrite ion, and nitrate ion in water can kill fish. Lethal concentrations of these specie

kykrilka [37]

Explanation:

It is known that molality is the number of moles present in kg of solution.

Mathematically, Molality = $\frac{\text{no. of moles of solute}}{\text{mass of solvent in Kg}}$

The given data is as follows.

Molar mass of ammonia = 17 g/mol

Concentration = 1.002 mg/L = $\frac{0.001002 g/L}{17 g/mol}$

= $5.89 \times 10^{-4}$ mol/L

Also, density = $\frac{1 g}{mL}$ = 1 kg/L

Therefore, molality will be calculated as follows.

Molality = $\frac{5.89 \times 10^{-4} mol/L}{1 kg/L}$

= $5.89 \times 10^{-4} mol/kg$

And,

Molar mass of nitrite = 46 g/mol

Concentration = 0.387 mg/L = $\frac{0.000412 g/L}{46 g/mol}$

= $8.956 \times 10^{-6}$ mol/L

And, density = $\frac{1 g}{mL}$ = 1 kg/L

Hence, molality = $\frac{8.956 \times 10^{-6} mol/L}{1 kg/L}$

= $8.956 \times 10^{-6}$ mol/kg

Now, Molar mass of nitarte = 62 g/mol

Concentration = 1352.2 mg/L

= $\frac{1.3522 g/L}{62 g/mol}$

= 0.02181 mol/L

Also, density = $\frac{1 g}{mL}$ = 1 kg/L

Hence, molality will be calculated as follows.

Molality = $\frac{0.02181 mol/L}{1 kg/L}$

= 0.02181 mol/kg

Therefore, molality of given species is $5.89 \times 10^{-4} mol/kg$ for ammonia, $8.956 \times 10^{-6}$ mol/kg for nitrite, and 0.02181 mol/kg for nitrate ion.

7 0

4 years ago

Which statement correctly describes the relationship between reactant and yield? The actual yield is calculated from the amount

melamori03 [73]

The statement which correctly describe the relationship between the reactants and the yield is this: 'the theoretical yield is calculated from the amount of the limiting reactants present'. The theoretical yields is the ideal maximum amount of a product that can be produced during a chemical reaction while the limiting reactant is the reactant that determines the maximum amount of product that can be formed.

8 0

4 years ago

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