False. ......................................
Answer:
- In general, polar solutes are most soluble in highly polar solvents.
Explanation:
The general rule is "like dissolves like" which means that <em>polar solvents </em>dissolve polar (or ionic) <em>solutes</em> and <em>non-polar solvents</em> dissolve non-polar solutes.
In order for a solvent dissolve a solute, the strength of the interacttion (force) between the solute and the solvent units (atoms, molecules, or ions) must be stronger than the strength of the forces that keep together he particles of the pure substances (known as intermolecular forces).
Since the nature of the interactions between the units are electrostatic, the more polar is the solvent the better it will be able to attract and surround the solute particles, keeping them separated and in solution. That mechanism explains why polar solutes will be most soluble in highly polar solvents.
Answer:
Yes because the law of conservation of matter is followed. There are equal numbers of atoms of all elements in the
reactants and products.
Explanation:
A balanced equation conform to the law of conservation of matter. While unbalanced equation suggests that matter has been created or destroyed.
Na3PO4 + 3KOH —> 3NaOH + K3PO4
A careful observation of the above equation proved that the equation is balanced is balanced because there are equal numbers of atoms of all elements in the
reactants and products.
Answer:
The scientific name of the grasshopper is Caelifera.
Explanation:
hope this helps.
Answer:
The concentration of the pyridinium cation at equilibrium is 1.00×10⁻³ M
Explanation:
In water we have
C₅H₅NHBr + H₂O ⇒ C₅H₅NH+ + Br−
Pyridinium Bromide (C₅H₅NHBr) Dissociates Completely Into C₅H₅NH+ And Br− as such it is a strong Electrolyte.
Therefore the number of moles of positive ion produced per mole of C₅H₅NHBr is one
pH = - log [H₃O⁺] Therefore 10^-pH = [H₃O⁺] = concentration of C₅H₅NHBr
= 10⁻³ = 0.001M = concentration of C₅H₅NHBr
The concentration of C₅H₅NHBr is = 1.00×10⁻³ M to two places of decimal
