Answer:
4 people
Explanation:
In order to know this, we need to gather the data.
First we have 3.5x10⁴ g of LiOH. This grams are to be last for the whole 9 days mission shuttle.
So, we first need to know how much of CO₂ will be neutralized by this mass. This can be done calculating the moles of LiOH, and then, the moles of CO₂
The molecular weight of LiOH is 23.94 g/mol and for CO₂ is 44 g/mol so:
CO₂ + 2LiOH -------> Li₂CO₃ + H₂O
moles of LiOH = 3.5x10⁴ / 23.94 = 1461.988 moles
We have a mole ratio of 1:2 so the moles of CO₂:
moles CO₂ = 1461.988 / 2 = 730.994 moles
The mass of CO₂ for the 9 days will be:
m CO₂ = 730.994 * 44 = 32163.74 g
Now, let's see how much it has to be used per day:
m CO₂/d = 32163.74 / 9 = 3573.75 g per day
This means that we can only take a few astronauts, and this number is:
n° astronaut = 3573.75 / 8.8x10²
<h2>
n° astronaut = 4.06</h2><h2>
In other words, only 4 astronaut</h2>
