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astra-53 [7]
3 years ago
10

Humans exhale carbon dioxide when they breathe. If the concentration of carbon dioxide in the air that

Chemistry
1 answer:
Verizon [17]3 years ago
3 0

Answer:

4 people

Explanation:

In order to know this, we need to gather the data.

First we have 3.5x10⁴ g of LiOH. This grams are to be last for the whole 9 days mission shuttle.

So, we first need to know how much of CO₂ will be neutralized by this mass. This can be done calculating the moles of LiOH, and then, the moles of CO₂

The molecular weight of LiOH is 23.94 g/mol and for CO₂ is 44 g/mol so:

CO₂ + 2LiOH -------> Li₂CO₃ + H₂O

moles of LiOH = 3.5x10⁴ / 23.94 = 1461.988 moles

We have a mole ratio of 1:2 so the moles of CO₂:

moles CO₂ = 1461.988 / 2 = 730.994 moles

The mass of CO₂ for the 9 days will be:

m CO₂ = 730.994 * 44 = 32163.74 g

Now, let's see how much it has to be used per day:

m CO₂/d = 32163.74 / 9 = 3573.75 g per day

This means that we can only take a few astronauts, and this number is:

n° astronaut = 3573.75 / 8.8x10²

<h2>n° astronaut = 4.06</h2><h2>In other words, only 4 astronaut</h2>
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Determine Δngas for each of the following reactions:(b) 2H₂(g) + O₂(g) ⇄ 2H₂O(l)
elixir [45]

2H₂(g) + O₂(g) ⇄ 2H₂O(l)

Δngas = 0 - (2 +1)

           = -3

<h3>What is Δngas?</h3>

The number of moles of gas that move from the reactant side to the product side is denoted by the symbol ∆n or delta n in this equation.

Once more, n represents the growth in the number of gaseous molecules the equilibrium equation can represent. When there are exactly the same number of gaseous molecules in the system, n = 0, Kp = Kc, and both equilibrium constants are dimensionless.

<h3>Definition of equilibrium</h3>

When a chemical reaction does not completely transform all reactants into products, equilibrium occurs. Many chemical processes eventually reach a state of balance or dynamic equilibrium where both reactants and products are present.

Learn more about Equilibrium

brainly.com/question/11336012

#SPJ4

5 0
1 year ago
ANSWERS NEEDED ASAP
Artemon [7]

1 and 2 the forces holding water molecules together are stronger than the forces holding alcohols molecules together these forces are stronger in water due to hydrogen bonding the intermolecular forces forces that hold the water together are stronger than alchol because water has hydrogen bonding hydrogen bonding is hydrogen being attracted to oxygen or flourine or chloroine the electronegativity differences are larger the forces holding the bonds are stronger its like hydrogen is holding on to oxygen strongly different types of forces are lomdon dispersion forces like helium which have low boiling point they have nothing holding them together water has hydrogen bonds alcohol doesnt have the hydrogen bonds water has and geometry vsper model polar and hydrogen bonds as water so theyre weaker.

3 0
3 years ago
A substance is analyzed and found to contain 85.7% carbon and 14.3% hydrogen by weight. A gaseous sample of the substance is fou
atroni [7]

Answer:

The empirical formula of the compound is CH2

Explanation:

<u>Step 1:</u> Data given

A substance contains 85.7 % carbon and 14.3 % hydrogen.

The substance has a density of 1.87 g/L

1 mol occupies 22.4 L

Molar mass of carbon = 12 g/mol

Molar mass of hydrogen = 1.01 g/mol

<u>Step 2</u>: Calculate molar mass of the substance

Since 1 mol occupies 22.4 L;

1 mol of this substance = 1.87g/L *22.4 = 41.888 grams

This means the molar mass of the substance is 41.888 g/mol

<u>Step 3:</u> Calculate mass of carbon:

85.8 % is carbon

this means 41.888 * 0.858 = 35.94 grams

<u>Step 4: </u>Calculate moles of carbon

moles C = mass C/ Molar mass C

Moles C = 35.94 grams / 12 g/mol

Moles C = 2.995 moles

<u>Step 5:</u> Calculate mass of hydrogen:

14.3 % is hydrogen

this means 41.888 * 0.143 = 5.99 grams

<u>Step 6 :</u>Calculate moles of hydrogen

Moles H  = 5.99 grams / 1.01 g/mol

Moles H = 5.93 moles

<u>Step 7: </u>Calculate  mol ratio

Ratio C:H = 1:2

The empirical formule = CH2

<u>Step 8</u>: calculate molar formule

Molar mass of empirical formule = 14.02 g/mol

n = Molar mass of substance / molar mass of empirical formule

n = 41.888 / 14.02 = 3

This means we have to multiply the empirical formula by 3

3*(CH2) = C3H6

C3H6 can be propene or cyclopropane

5 0
2 years ago
A mixture of hydrochloric and sulfuric acids is prepared so that it contains 0.315 M HCl and 0.125 M H2SO4. What volume of 0.55
Xelga [282]

<u>Answer:</u> The volume of NaOH required is 402.9 mL

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}     .....(1)

  • <u>For HCl:</u>

Molarity of HCl solution = 0.315 M

Volume of solution = 503.4 mL = 0.5034 L   (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

0.315M=\frac{\text{Moles of HCl}}{0.5034L}\\\\\text{Moles of HCl}=(0.315mol/L\times 0.5034L)=0.1586mol

  • <u>For sulfuric acid:</u>

Molarity of sulfuric acid solution = 0.125 M

Volume of solution = 503.4 mL = 0.5034 L

Putting values in equation 1, we get:

0.125M=\frac{\text{Moles of }H_2SO_4}{0.5034L}\\\\\text{Moles of }H_2SO_4=(0.125mol/L\times 0.5034L)=0.0630mol

As, all of the acid is neutralized, so moles of NaOH = [0.1586 + 0.0630] moles = 0.2216 moles

Molarity of NaOH solution = 0.55 M

Moles of NaOH = 0.2216 moles

Putting values in equation 1, we get:

0.55M=\frac{0.2216}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{0.2216}{0.55}=0.4029L=402.9mL

Hence, the volume of NaOH required is 402.9 mL

6 0
2 years ago
What is the boiling point of water at 1 atm in Kelvin
nevsk [136]

Answer:100 °C

Explanation:

8 0
3 years ago
Read 2 more answers
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